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3 years ago

Is a street the same as a avenue

Engineering

2 answers:

-BARSIC- [3]3 years ago

5 0

they're essentially the same thing so i'd say yes

Whitepunk [10]3 years ago

5 0

Answer:

there kinda the same

Explanation:

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A circular ceramic plate that can be modeled as a blackbody is being heated by an electrical heater. The plate is 30 cm in diame

denis23 [38]

Answer:

Q = 125.538 W

Explanation:

Given data:

D = 30 cm

Temperature $T_\infity = 15$ degree celcius

$T_S = 220 + 273 = 473 K$

Heat coefficient = 12 W/m^2 K

Efficiency 80% = 0.8

$Q = hA(T_S - T_{\infty}) \eta$

$= 12(\frac{\pi}{4} 0.3^2) (473 - 288) 0.8$

Q = 125.538 W

5 0

3 years ago

Of the following answers, which is NOT a way for employees to control exposure routes?

Katena32 [7]

Answer: Of the following answers, which is NOT a way for employees to control exposure routes?

Explanation:

4 0

3 years ago

a centrifugal pump delivers water at the rate of 50kg/is . the inlet and outlet pressure are 2 bar and 6.2 bar respectively. the

Monica [59]

Answer:

21.6 kw

Explanation:

Given data:

m = 50 kg/s

Inlet pressure (p1) = 2 bar

outlet pressure(p2) = 6.2 bar

suction ( h1 ) = -2.2 m

delivery ( h2 ) = 8.5 m

d1 = 200 mm = 0.2 m

d2 = 100 mm = 0.1 m

Vs of water = 0.001 m^3/kg

next we have to determine the Q value

Q = V*A

Q = 0.001 * 50 = 0.05 m^3/s

next we have to calculate the various V's

V1 = Q/A1 = $\frac{0.05*4}{\pi *0.2^2}$ = 1.59 m/s

V2 = Q/A2 = $\frac{0.05*4}{\pi *0.1^2}$ = 6.37 m/s

Determine the capacity of the electric motor

attached below is the detailed solution

7 0

3 years ago

Tanya Pierce, President and owner of Florida Now Real Estate is seeking your assistance in designing a database for her business

const2013 [10]

Answer:

the answer is attributes for each entity

5 0

4 years ago

Air enters a compressor at 100 kPa and 25 ⁰C. It is compressed to 2 MPa and exits the compressor at 540 K. The compressor is at

AysviL [449]

Answer:

(a) The reversible work is 207 kJ/kg

(b) The irreversibility rate is -38.39 kJ/kg

Explanation:

State1 : p1 = 100kpa, T1= 25+273 =298k

From air table, h1 =298.18 kJ/kg, s10= 1.69528 kJ/kgK

State 2a:p2=2mpa,t2=540k (actual condition 2a)

h2a= 544.35 kJ/kg,s2a0=2.29906

actual work input to the compressor =wout=h1-h2+Qin

=298.18-544.35+(-150)kJ/kg(- sign indicate heat loss)

=(-246.17)kJ/kg(-ve sign indicates the work is given into the system

a) Reversible work= Win actual - any irreversiblities present

=246.17 + irreversibilty

b) irreversibility = T0(Entopy generation Sgen) for air, Sgen

=s20-s10-Rln(p2/p1), T0=250C

=(25+273)(s2a0-s10-Rlnp2/p1+Qout/Tsurr)

= 298x[(2.29906-1.69528-0.287kJ/kgK xln(2000kpa/100) + 150 /298]

= -38.39 kJ/kg

a)Reversible work = Win actual -any irreversiblities present

=246.17 + irreversibilty

=246.17+-38.39

=207 kJ/kg

8 0

3 years ago