In the lab, a container of saturated soil had a mass of 113.27 g before it was placed in the oven and100.06 g after the soil had dried. The container alone had a mass of 49.31 g. If the specific gravity ofsolids is 2.80, determine the void ratio and water content of the original soil sample.
1 answer:
Answer:
Moisture/ water content w = 26% Explanation:
Initial mass of saturated soil w1 = mass of soil - weight of container = 113.27 g - 49.31 g = 63.96 g
Final mass of soil after oven w2 = mass of soil - weight of container = 100.06 g - 49.31 g = 50.75
Moisture /water content, w = = = 0.26 = 26%
Void ratio = water content X specific gravity of solid
= 0.26 X 2.80 =0.728
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