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2 years ago

Complete the following reaction. 14N+ on →?C+1H 18C 14 1 C 18C

Chemistry

1 answer:

CaHeK987 [17]2 years ago

6 0

Answer: The complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

Explanation:

When nucleus of two or more atoms are bombarded together then it leads to the formation of new particles with new identity. This type of reaction are called nuclear reaction.

For example, $^{14}_{7}N + ^{1}_{0}n \rightarrow ?C + ^{1}_{1}H$

Here, nitrogen atom when bombarded with a neutron then it is forming hydrogen and a carbon atom.

As total atomic mass on reactant side is (14 + 1) = 15

So, the atomic mass of carbon formed on product side is (15 - 1) = 14.

The number of protons holded by this carbon atom is (7 - 1) = 6.

Therefore, we can conclude that the complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

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<u>structural arrangements</u>

_______________________________________

<h2>properties of daimond: </h2><h3>appearance: transparent</h3><h3>hardness: very hard</h3><h3>thermal conductivity :very poor</h3><h3>electric conductivity: poor</h3><h3>density:</h3>

$3510 {kgm}^{3}$

<h3>uses: jewellery and drilling</h3>

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<h2>properties of graphite:</h2>

<h3>appearance: black shiny</h3><h3>hardness: soft ,slippery to touch</h3><h3>thermal conductivity : moderate</h3><h3>electric conductivity: good</h3><h3>density:</h3>

$2250 {kgm}^{3}$

<h3>uses:dry cell, electric arc, pencil lead, lubricant</h3>

_______________________________________

<h2>How Diamond and Graphite are chemically identical?</h2>

On heating diamond or graphite in the air, they burn completely to form carbon dioxide.
- Equal quantities of diamond and graphite when burned, produce exactly the same amount of carbon dioxide.

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<h2>Why the physical properties of diamond and graphite are so different?</h2>

Due to the difference in the arrangement of carbon atoms in diamond and graphite

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<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>