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3 years ago

Complete the following reaction. 14N+ on →?C+1H 18C 14 1 C 18C

Chemistry

1 answer:

CaHeK987 [17]3 years ago

6 0

Answer: The complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

Explanation:

When nucleus of two or more atoms are bombarded together then it leads to the formation of new particles with new identity. This type of reaction are called nuclear reaction.

For example, $^{14}_{7}N + ^{1}_{0}n \rightarrow ?C + ^{1}_{1}H$

Here, nitrogen atom when bombarded with a neutron then it is forming hydrogen and a carbon atom.

As total atomic mass on reactant side is (14 + 1) = 15

So, the atomic mass of carbon formed on product side is (15 - 1) = 14.

The number of protons holded by this carbon atom is (7 - 1) = 6.

Therefore, we can conclude that the complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

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Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

$ln(K)=\frac{\Delta _RG}{RT}$

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

$Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}$

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

8 0

3 years ago

Read 2 more answers

Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3

Margarita [4]

Answer: The rate law for the reaction is $\text{Rate}=k'[H+][H_2O_2][Br^-]$

Explanation:

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

$2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O$

The intermediate reaction of the mechanism follows:

Step 1: $H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}$

Step 2: $H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}$

Step 3: $HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}$

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

$\text{Rate}=k[H_3O_2^+][Br^-]$ ......(1)

As, $[H_3O_2^+]$ is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for $[H_3O_2^+]$ from step 1, we get:

$K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}$

$[H_3O_2^+]=K[H^+][H_2O_2]$

Putting the value of $[H_3O_2^+]$ in equation 1, we get:

$\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]$

Hence, the rate law for the reaction is $\text{Rate}=k'[H+][H_2O_2][Br^-]$

4 0

3 years ago

You have been asked to draw a Bohr model of the element carbon. How would you arrange the dots that represent electrons?

Dvinal [7]

Answer:

You have been asked to draw a Bohr model of the element carbon. How would you arrange the dots that represent electrons? They would be embedded in a solid core. They would be in rings around the nucleus

7 0

2 years ago

Compare and contrast elements and compunds

Firdavs [7]

Answer:

The similarity is that Elements and Compunds exist in stable form because of the bonds formed between their atoms. The difference is that an element is a material that consists of a single type of atom and a compound consists of two or more types of elements held together by covalent or ionic bonds.

Explanation: Google

3 0

3 years ago

A 60.0 kg object is moving east at 8.00 m/s, and then slows down to 4.00 m/s. How much work was done?

Colt1911 [192]

Answer:

-1440J

Explanation:

Hello,

This question requires us to calculate the work done on a object to move it from point A to point B

Data

Mass = 60kg

Initial velocity (V1) = 8.0m/s

Final velocity (V2) = 4.0m/s

Workdone on an object is equal to force applied on the object to move it through a particular distance.

Work done = force × distance

Force (F) = mass × acceleration

Distance = s

F = Ma

Work done = M× a × s

But a = velocity (v) / time (t)

Work done = mvs / t

But velocity = distance/ time

Work done = mv × v/

Work done = mv²

Work done = ½mv²

Workdone = ½M(V2² - V1²)

Workdone = ½ × 60 (4² - 8²)

Work done = 30 × (16 - 64)

Workdone = 30 × (-48)

Work done = -1440J

Work done = -1.44kJ

The workdone on the object is equal to -1.44kJ

5 0

3 years ago