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Viktor [21]
4 years ago
7

A thread is being pulled off a spool at the rate of 57.3 cm per sec. Find the radius of the spool if it makes 141 revolutions pe

r min. Round to two decimal places as needed.
Physics
1 answer:
oksano4ka [1.4K]4 years ago
4 0

Answer: r= 0.04meter

Explanation:

The velocity V and angular speed w is related to the radio by

V=w*r

r=V/w

But the standard unit for velocity is m/s so we convert 57.3cm/sec to m/s

57.3/100= 0.57m/s

Also Angular speed w is rad/secs

So we convert rev/min to rad/sec

0.1rad/sec equals 1 rev/mins

141rev/mins * 0.1rad/secs

=14.1rad/sec

r = V/w

= 0.573/14.1

= 0.04m to 2d.p

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Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce
NemiM [27]

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b. 450 nm

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Δx = λL/d

Δx/2 = λL/2d

where,

Δx/2 = half distance between consecutive dark fringes = width of central maximum = 0.75 cm = 0.0075 m

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L = Distance of Screen = 1.25 m

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Therefore,

0.0075 m = λ(1.25 m)/(0.00015 m)

λ = (0.0075 m)(0.00015 m)/2(1.25 m)

λ = 4.5 x 10⁻⁷ m = 450 nm

Thus, the correct option is:

<u>b. 450 nm</u>

8 0
3 years ago
Which of the following vehicles has the most kinetic energy? A. a 300kg motorcycle traveling 60km/h B. a 1,100kg car traveling 6
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Explanation:

Kinetic energy of an object is given by :

E=\dfrac{1}{2}mv^2

Where

m is mass and v is velocity of the object

A. Mass, m = 300 kg.

Speed, v = 60 km/h = 16.67 m/s

E=\dfrac{1}{2}\times 300\times 16.67^2\\\\=41683.33\ J

B. Mass, m = 1100 kg.

Speed, v = 60 km/h = 16.67 m/s

E=\dfrac{1}{2}\times 1100\times 16.67^2\\\\=152838.89\ J

C. Mass, m = 900 kg.

Speed, v = 80 km/h = 22.22 m/s

E=\dfrac{1}{2}\times 900\times 22.22^2\\\\=222177.78\ J

D. Mass, m = 2000 kg.

Speed, v = 50 km/h = 13.88 m/s

E=\dfrac{1}{2}\times 2000\times 13.88^2\\\\=192654.4\ J

The kinetic energy in case C is maximum.

7 0
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