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3 years ago

Can someone please help me quickly!!!

Chemistry

2 answers:

galina1969 [7]3 years ago

4 0

Answer:

Mercury

Explanation: Under standard conditions mercury is a shiny, heavy, silvery liquid. It is the only metal that is liquid at room temperature.

pantera1 [17]3 years ago

3 0

Answer:

Mercury, Venus, earth and mar, Jupiter, Saturn, urines, Neptune.

Explanation:

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A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago

Calculate the work associated with the compression of a gas from 121.0 l to 80.0 l at a constant pressure of 16.7 atm.

Molodets [167]

I’m am most positive the answer is c. For cat

6 0

3 years ago

If a sample of gas at constant temperature has its pressure doubled, what will happen to its volume?

kozerog [31]

Answer:

it'll halve

Explanation:

the gas is compressed with twice the pressure. The volume will be halved.

im certain

6 0

2 years ago

The solid XY decomposes into gaseous X and Y: XY(s) m X(g) + Y(g) Kp = 4.1 (at 0 °C) If the reaction is carried out in a 22.4 L

tia_tia [17]

Answer:

None of the conditions will favor either the forward reaction or backward reaction , hence the answer is D

Explanation:

The principle of chemical Equilibrium is applied here, where the concentration of the reactants or the forward reaction is same as the concentration of the products or the backward reaction.

The equilibrium constants is also involved here, K can be in terms of pressure (Kp) or concentration (Kc) hence equilibrium constant is the ration of the concentration of the products to the concentration of the reactants raised to the power of the coefficient of the reactants and products.
Partial pressure , total pressure and the mole fraction relationship is also applied
The step by step explanation is as shown in the attachment below.

4 0

3 years ago

Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.

NARA [144]

PH is the test of acidity or basicity of a solution. it follows the formula:
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case.

By literature, Ka of HF is 3.5*10^-4
pKa= -log(Ka)= 3.46 

pH = pKa + log [NaF / [HF] 

4.05 = 3.46 + log [NaF / [HF]

log [NaF / [HF] = 0.59

[NaF / [HF] = 3.89

4 0

4 years ago

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