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Vilka [71]
3 years ago
11

A sample of hydrogen gas, has a volume of 8.56 L at a temperature 0oC and pressure of 1.5 atm. Calculate the number of moles of

hydrogen present in this gas sample ( Assume that the gas behave ideally)
Chemistry
1 answer:
erica [24]3 years ago
3 0
P = 1.5atm ≈ 1519.88hPa
V = 8.56L
R = 83.1 [hPa*L] / [mol*K]
T = 0°C =273K

pV = nRT   |:RT

n = pV / RT

n = [1519.88hPa*8.56L] / [83.1 [hPa*L] / <span>[mol*K] * 273K]
n </span>≈ <u>0.57mol</u><span><u> </u></span>
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254950m to millimeter
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I begin the reaction with 0.45 g of beryllium. If my actual yield of beryllium chloride (mm = 79.91 g/mol) was 3.5 grams, what w
trasher [3.6K]

The percentage of yield was 777.78%

<u>Explanation:</u>

We have the equation,

Be [s]  +  2 HCl [aq]  →  BeCl 2(aq]  + H 2(g]  ↑ Be (s]  + 2 HCl [aq]  →  BeCl 2(aq]  + H 2(g] ↑

To find the percent yield we have the formula

Percentage of Yield= what you actually get/ what you should theoretically get  x 100

                                   =3.5 g/0.45 g 100

                                    = 777.78 %

The percentage of yield was 777.78%

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3 years ago
Write the formulas of the three singly chlorinated isomers formed when 2,2-dimethylbutane reacts with Cl2 in the presence of lig
Tems11 [23]

The molecule with same molecular formula but different arrangement of atoms is said to be an isomer.

When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is CH_{3}C(CH_{3})_{2}CHClCH_{3} (3-chloro-2,2-dimethylbutane), ClCH_{2}C(CH_{3})_{2}CH_{2}CH_{3} (1-chloro-2,2-dimethylbutane) and ClCH_{2}CH_{2}C(CH_{3})_{2}CH_{3} (1-chloro-3,3-dimethylbutane).

In above case, the molecular formula of all isomers are same i.e.C_{6}H_{13}Cl but chlorine is arranged in different positions of carbon. Thus, results isomers.

The reaction is shown in the image.


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3 years ago
Use the Periodic Table. Choose the correct electron configuration of carbon using the data shown in the electron configuration c
AleksAgata [21]

I think I have done a question like this before and i'm pretty sure your answer would be the 2nd one 1s22s22p4. I'm not 100% sure but try it at least.

4 0
3 years ago
Read 2 more answers
How many water molecules are in a block of ice containing 0.500 mol of water (H2O)?
Alex Ar [27]

Answer:

3.01 × 10²³ molecules

Explanation:

Step 1: Given data

Moles of water (n): 0.500 mol

Step 2: Calculate the molecules of water present in 0.500 moles of water

In order to perform this calculation, we will use the Avogadro's number: in 1 mole of water there are 6.02 × 10²³ molecules of water.

0.500 mol × (6.02 × 10²³ molecules/1 mol) = 3.01 × 10²³ molecules

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