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Burka [1]
3 years ago
12

The following figure shows the tensile stress-strain curve for a brass alloy.

Engineering
1 answer:
Aleksandr-060686 [28]3 years ago
7 0
(A)-The Theoretical Strength Is Higher Than The Experimental Strength.

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Three parallel three-phase loads are supplied from a 480V (line-line RMS), 60 Hz three-phase supply. The loads are as follows: L
Travka [436]

Answer:

The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Explanation:

Load 1: Active power P_1 = 20 HP = 14.91kW;

Reactive power Q1 = P tan(\phi)

                               = 14.91\times tan(cos^{-}0.8) = 11.18 kvar


Load 2: Active power P_2 = 20 kW;

Reactive power Q2 = 0 since the load is purely resistive.

Load 3: Active power P_3 = 0 due to purely capacitiveload

           Reactive power Q_3 = -20 Var

a) since all three loads are connected in parallel therefore

    The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Total system reactive power Q = Q_1 + Q_2 + Q_3 = 11.18 + 0 -20 = -8.82 kVar

Since Q = 0, the power factor is unity.

Supply current per phase is given by

I = \frac{P}{\sqrt{3}V_{L}}

= \frac{34910}{\sqrt{3}\times 480} = 41.99 A

5 0
3 years ago
scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minu
ladessa [460]
Answer is: 12.8 because when you multiply it by the 2nd power of 8 then the scraper equals to be 12.8 in height and that’s how much each scraper requires to operate :)
7 0
3 years ago
A square steel bar has a length of 8.4 ft and a 2.1 in by 2.1 in cross section and is subjected to axial tension. The final leng
nikitadnepr [17]

Answer:

Poissons ratio = -0.3367

Explanation:

Poissons ratio = Lateral Strain / Longitudinal Strain

In this case, the longitudinal strain will be:

Strain (longitudinal) = Change in length / total length

Strain (longitudinal) = (8.40392 - 8.4) / 8.4

Strain (longitudinal) = 4.666 * 10^(-4)

While the lateral strain will be:

Strain (Lateral) = Change in length / total length

Strain (Lateral) = (2.09967 - 2.1) / 2.1

Strain (Lateral) = -1.571 * 10^(-4)

Solving the poisson equation at the top we get:

Poissons ratio = -1.571 / 4.666                                     <u>( 10^(-4) cancels out )</u>

Poissons ratio = -0.3367

6 0
4 years ago
Calculate the diameter of pneumatic cylinder to drive a mechanism. The force exerted by the mechanism is 80 N. The return force
sashaice [31]

Answer:

14.27 mm

Explanation:

Force = 80 Newton

Pressure exerted = 5 bar = 5×10⁵ Pa

Pressure exerted = Force/Area

Area = Force/Pressure

Area=\frac{80}{500000}\\\Rightarrow Area=0.00016\ m^2

Area of the cylinder=πd²/4

\Rightarrow \frac{\pi}{4}d^2=0.00016\\\Rightarrow d^2=\frac{4\times 0.00016}{\pi}\\\Rightarrow d^2=0.0002037\\\Rightarrow d=0.01427\ m

Hence diameter of cylinder 14.27 mm

5 0
3 years ago
If you think a hazard is serious, what is the best way to ensure that OSHA will
Umnica [9.8K]

Answer:

The best way to ensure that OSHA will conduct a site inspection is by the submission a signed (by a current employee or employee representative) Formal Written complaints following OSHA guidelines (which can be found in the  Council of Safety and Health (COSH) website) which will enable the commencement of process for an on site inspection

As such it is advisable to go through the following procedure before, filing a complaint

1) Talk to your workers union about the hazard

2) If you do not belong to a union, talk to your co-workers

3) Inform your employer who has responsibility for on the job safety

4) Speak or have a meeting with OSHA so as to receive guidance before filing a complaint

Explanation:

3 0
3 years ago
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