Answer:power source or battery
Explanation:
Answer:
It will be around 146,27 min since the pump is turned on until the deck is clear of the water.
Explanation:
When the leak is discovered and the pump is turned on, the lower deck is already submerged and the leak is not fixed; then, in order to have the deck clear of water, the bilge pump has to remove the <em>accumulated water </em>(
) and the <em>water that is taking on</em> (
) through the leak. We can represent this mathematically as follow:
<em>Equation 1</em>
Where:
: is the accumulated water when the leak was discovered
: is the takes on rate through the leak = 57.5 gal/min
: is the removing rate of the bilge pump = 73.8 gal/min
t= is the time since the pump is turned on until the deck is clear of water.
To calculate the accumulated water (), we will model the lower deck as a flat-bottomed container with a bottom surface area of 510 
and straight vertical sides. Knowing that the level submerged is 7.5 inches, and performing the corresponding unit conversions, we obtain:
= bottom surface area * lever submerged
<em>Equation 2</em>
Solving equation 1 for time (t), and replacing the value obtained in equation 2, we get:
146,27 min
It is called a ‘Waste Stream’
This should be right! Hope this helps, have a great day!
Answer:
In this phase, the detailed user documentation is created that highlights how to use the system and how to troubleshoot issues or problems.
Explanation:
its all i got sorry but hope it helps a lil
Answer:
Q= 6491.100 kJ/s
Explanation:
Air-Fuel Ratio:
For a combustion reaction the proportion of air that is present in a gaseous substance responsible for the reaction,this proportion is known as air-fuel ratio.The air fuel ratio is calculated using the combustion reaction for the substance.
Considering reaction for the Ethanol as
C₂H₅OH +XO₂(O₂+3.76N₂)→ aCO₂+bH₂O+cN₂
Balancing the equation we get;
a=2,
2b=6
∴ b=3
xO₂=3
The air-fuel ratio
A/F = XO₂+H₂O+xN₂× mass of N₂/mass(fuel)
3.31×31.9+11.28×28.013/46.069
= 8.943
Equivalent ratio = 0.7,
so, heat transfer
Q= m ×Cp×ΔT
= 75×0.7×112.4(1500-400)
Q= 6491.100 kJ/s
1kJ/s=1000w
∴ Q= 6491100 W
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