Answer:
V = 0.896 m/s
Explanation:
This is a typical problem of momentum conservation, whic states the following:
m₁V₁ + m₂V₂ = m₁V₃ + m₂V₄ (1)
In this case V₃ and V₄ would be the final velocity of the trucks after the collision.
With the given data let's see what we have:
m₁ = 5.5x10⁵ kg
m₂ = 2.3x10⁵ kg
V₁ = 5 m/s
V₂ = -5 m/s because it's going to the left (-x axis)
V₄ = 9.1 m/s to the right (Meaning is positive)
V₃ = ??
So to calculate V₃ we just need to replace the data into (1) and solve for V₃:
(5.5x10⁵ * 5) - (2.3x10⁵ * 5) = 5.5x10⁵V₃ + (2.3x10⁵ * 9.1)
2.75x10⁶ + 1.15x10⁶ = 5.5x10⁵V₃ + 2.093x10⁶
V₃ = 2.75x10⁶ - 1.15x10⁶ - 2.093x10⁶ / 5.5x10⁵
V₃ = -0.493x10⁶ / 5.5x10⁵
V₃ = -0.896 m/s
With this sign, it means that is going in the same sense of the other truck, but it's going to the left so this would be positive:
<h2>
V₃ = 0.896 m/s</h2>
Hope this helps
Answer: Generally, prevailing winds blow east-west rather than north-south. This happens because Earth's rotation generates what is known as the Coriolis effect. The Coriolis effect makes wind systems twist counter-clockwise in the Northern Hemisphere and clockwise in the Southern Hemisphere.
Explanation: here u go
Given:
Circumference = 2 m
Angular speed, ω = 1 rev/s = 2π radians/s
If the radius is r, then
2πr = 2
r = 1/π m
The linear (tangential) speed is
v = rω
= (1/π m)*(2π rad/s) = 0.5 m/s
Answer: 0.5 m/s
Answer: The distance covered by a certain object which is travelling at a certain speed is calculated through the equation,
d = (V₀)t + 0.5at²
where d is the distance, V₀ is the initial speed, a is deceleration, and t is the time. Substituting the known values,
85 = (V₀)(t) + (0.5)(-0.43 m/s)(t²)
Because we are not given with the initial velocity, our answer would remain as the equation which is written above.
Explanation: Hope this helps
Answer:
227 m/s
Explanation:
Kinetic energy formula:
- where m = mass of the object (kg)
- and v = speed of the object (m/s)
Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.
First convert the mass to kilograms:
Plug known values into the KE formula.
Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.
First convert the mass to kilograms:
Plug known values into the KE formula.
The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.