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Sati [7]
2 years ago
12

A balloon contains helium gas. Which applies to the volume of the gas in the balloon when pressure is increased at constant temp

erature?
A.
the volume of the gas increases

B.
the volume of the gas decreases

C.
the average speed of the gas molecules decreases

D.
the total number of gas molecules remains the same
Physics
1 answer:
svetlana [45]2 years ago
8 0

Answer:

the volume of the gas decreases

Explanation:

As a balloon rises through the atmosphere, the air pressure around it decreases and the balloon expands.

Good luck!

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True or false it is impossible to determine weather you are moving unless you can touch another object
Lerok [7]

Answer: false

Explanation:

4 0
3 years ago
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How can you tell if an igneous rock has an intrusive or extrusive origin?
wariber [46]

Intrusive igneous rocks cool down from magma slowly because they form underneath the surface, that will make them have large crystals.

Extrusive igneous rocks cool down from lava rapidly because they form at the surface, so that will make them have small crystals.

4 0
2 years ago
If there is a huge boulder on your lawn and you want to determine its density, but it is
Olin [163]

There are different options here but all of them work by approximating and assuming.

i) that the boulder is above ground.

ii) that the bottom surface of the boulder is known.

iii) the shape of the boulder is taken into account.

The most accurate way is measuring it by displacement method but the boulder is immovable hence the volume can be calculated by measuring the boulder or a waterproof box to be built around the boulder and calculate the volume occupied by boulder.

All the above methods are estimating methods.

*Another way to find the density is through specific gravity.

S.G = <u>Density</u><u> </u><u>of</u><u> </u><u>object</u>

Density of water

If the material that makes the boulder is known that is if it's stone or a mineral then the specific gravity can be found.

If the boulder is purely rock then S.G lies between 3 - 3.5 and the density of water is known thus the density of the boulder can be found without moving the boulder.

This is what I think after correction and allthe best!

3 0
2 years ago
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An object is launched with an initial velocity of 50.0 m/s at a launch angle of 36.9∘ above the horizontal. part a determine x-v
ankoles [38]
Given:
v = 50.0 m/s, the launch velocity
θ = 36.9°, the launch angle above the horizontal

Assume g = 9.8 m/s² and ignore air resistance.
The vertical component of the launch velocity is
Vy = (50 m/s)*sin(50°) = 30.02 m/s

The time, t, to reach maximum height is given by
(30.02 m/s) - (9.8 m/s²)*(t s) = 0
t = 3.0634 s
The time fo flight is 2*t = 6.1268 s

The horizontal velocity is
u = (50 m/s)cos(36.9°) = 39.9842 m/s
The horizontal distance traveled at time t is given in the table below.

Answer:

  t, s    x, m
------  --------
     0   0
     1   39.98
     2   79.79
     3   112.68
     4   159.58
     5   199.47
     6   239.37

5 0
3 years ago
Read 2 more answers
Can someone plz help me with this
Elena-2011 [213]
1st Law: Objects that are in motion tend to stay in motion. This motion can change with external forces. 

<span>If you were to stop pedaling on bike while in motion, you will notice that you will keep moving. This is because a moving body (you) has inertia. If there wasn't any friction between the tires and the ground, between the axles and wheel, any air resistance, or any other force that acts against you, then you could be coasting indefinitely! </span>

<span>2nd Law: Force is equal to the mass times acceleration. </span>

<span>When you pedal, you are applying a force onto the pedal. This force is then translated through tension to apply torque onto the wheel. Turning the wheel will make you accelerate in the lateral direction. </span>

<span>3rd Law: For every action, there is an equal and opposite reaction. </span>

<span>Without this, you could pedal and pedal, but you will be not go anywhere! It is essentially the friction between the tires and the ground that propels you forward. If the ground did not apply to the tire the same amount of force that the tire was applying to the ground, the tire would not "catch" and no friction would be applied. And if there was no third law, the weight of you and your bike would "sink" into the ground because the ground would not be applying a normal force back onto you.

hope this helps and if you have any questions just hmu and ask :)</span>
3 0
3 years ago
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