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Amiraneli [1.4K]
3 years ago
11

The sink-float method is often used to identify the type of glass material found at crime scenes by determining its density.Seve

ral different types of glass of known density are placed into solutions of varying densities. Determine whether each glasspiece will sink, float, or do neither when immersed in the given solution.Glass that will sinkGlass that will floatGlass that will not sink or floatalkali zinc borosilicate with a density of2.57 g/mL in a solution with a densityof 2.46 g/mLsoda borosilicate with a density of 2.27 g/mLin a solution with a density of 2.62 g/mLalkali strontium with a density of 2.26 g/mL ina solution with a density of 2.34 g/mLpotash borosilicate with a density of2.16 g/mL in a solution with a densityof 2.16 g/mLpotash soda lead with a density of 3.05 g/mLin a solution with a density of 1.65 g/mLAnswer Bankterms of usecontac
Chemistry
1 answer:
ch4aika [34]3 years ago
6 0

Answer:

Glass that will sink: alkali zinc borosilicate with a density of2.57 g/mL in a solution with a density of 2.46 g/mL; potash soda lead with a density of 3.05 g/mL in a solution with a density of 1.65 g/mL

Glass that will float: soda borosilicate with a density of 2.27 g/mL in a solution with a density of 2.62 g/mL; alkali strontium with a density of 2.26 g/mL in a solution with a density of 2.34 g/mL

Glass that will not sink or float: potash borosilicate with a density of2.16 g/mL in a solution with a density of 2.16 g/mL

Explanation:

The density of an object is a ratio of the mass (or quantity of matter in the object) to its volume.

Mathematically, density = mass/ volume.

The more dense an object, the higher will be its dense. Density can be thought of as a comparison of how heavy objects having the same are. Objects with a higher density, are heavier than objects with a lower density. For example, between equal volumes of air and water, water is heavier.

The density of solid object will determine whether it will float, sink or neither float nor sink in a given liquid. The conditions for floating of objects in a liquid is given as follows:

Density of solid > Density of liquid : solid will sink

Density of solid = Density of liquid : solid will neither sink nor float

Density of solid < Density of liquid : solid will float

Using the above criteria to analyze the given glass materials in their respective liquids:

Glass that will sink: alkali zinc borosilicate with a density of2.57 g/mL in a solution with a density of 2.46 g/mL; potash soda lead with a density of 3.05 g/mL in a solution with a density of 1.65 g/mL

Glass that will float: soda borosilicate with a density of 2.27 g/mL in a solution with a density of 2.62 g/mL; alkali strontium with a density of 2.26 g/mL in a solution with a density of 2.34 g/mL

Glass that will not sink or float: potash borosilicate with a density of2.16 g/mL in a solution with a density of 2.16 g/mL

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3 years ago
Which element is least metallic?<br><br> zinc<br> iron<br> cadmium<br> silver
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The reaction that occurs in a Breathalyzer, a device used to determine the alcohol level in a person's bloodstream, is given bel
Umnica [9.8K]

Answer:

The rate of disappearance of C₂H₆O = 2.46 mol/min

Explanation:

The equation of the reaction is given below:

2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O

From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.

The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus,  the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.

Rate of disappearance of C₂H₆O = 1.64 mol/min of  Cr₂(SO₄)₃  * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃

Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O

Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min

4 0
3 years ago
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The balanced equation of the reaction will be:

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Ca_{(aq)}^{2+}+2(NO_3)_{(aq)}^-+2Na_{(aq)}^++S_{(aq)}^{2-}\operatorname{\rightarrow}CaS_{(s)}+2Na_{(aq)}^++2NO^-_{3(aq)}

So, the answer will be option A

5 0
2 years ago
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