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3 years ago

Use the electron configurations and the periodic table to answer the questions:

Chemistry

2 answers:

Kaylis [27]3 years ago

7 0

The given electronic configuration indicates Fluorine (F).

Explanation:

The electronic configuration of each and every element in the periodic table reflects its character, stability and their chemical as well as physical properties.

It is given that 1s 2p that means 1s, 2s orbitals are filled and then 2p orbitals are maximum filled, then it contains 9 electrons, that is 2 electrons in 1s orbital, then 2 electrons in 2s orbital then 5 electrons in the 2p orbital.

So 1s² 2s² 2p⁵ is the electronic configuration indicates the element fluorine (F).

sergejj [24]3 years ago

4 0

Answer:

nitrogen

Explanation: just did it on edg

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The amount of energy it takes to remove an electron from an atom is

lara31 [8.8K]

the first ionization energy of an element is the energy needed toremove the outermost, or highest energy, electron from a neutral atom in the gas phase.

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3 years ago

a sample of an unknown metal has a mass of 21.6g and volume of an 8.00cm3 calculate the density of the unknown metal

Strike441 [17]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{21.6}{8} \\ = 2.7$

We have the final answer as

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3 years ago

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shusha [124]

Answer:

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3 years ago

WILL GIVE BRANLIEST!! Carbon tetrachloride (CCl4) is ionic covalent

monitta

Answer:

Covalent

Explanation:

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3 years ago

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For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an

Mnenie [13.5K]

Answer: 1) $2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

Equilibrium constant is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

$K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}$

where [] = concentration in Molarity= $\frac{moles}{\text {Volume in L}}$

Thus $[H_2S]=\frac{68.5}{1.0}=68.5M$

$[H_2]=\frac{0.50}{1.0}=0.50M$

$[S_2]=\frac{0.020}{1.0}=0.020M$

$K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=938450$

As the value of K is greater than 1, the reaction is product favored.

2) $N_2O_4(g)\rightleftharpoons 2NO_2(g)$

$K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}$

$K_{eq}=\frac{[0.500]^2}{[0.0250]}=10$

3) $N_2+3H_2\rightleftharpoons 2NH_3$

$K_{eq}=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

4) Reactions which do not continue to completion are called equilibrium reactions as the rate of forward reaction is equal to the rate of backward direction.

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3 years ago

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