D. would be my guess im almost positive that its right
The correct answer is In2O3 < Ga2O3 < Al2O3.
Ga2O3, Al2O3, and In2O3 are the oxides to rank in order of increasing aqueous acidity.
According to the contemporary periodic table's rule, an oxide group's acidity decreases.
The oxidation state of Gallium (Ga) in Ga2O3 = +3
The oxidation state of Aluminium (Al) in Al2O3 = +3
The oxidation state of Indium (In) in In2O3 = +3
From modern periodic table, the order of elements in group 3A is as below:
Baron (B), Aluminum (Al), Gallium (Ga), Indium (In), and Thallium (Tl)
Thus, we can get the oxides in order of increasing their aqueous acidity as below:
In2O3 < Ga2O3 < Al2O3
To learn more about aqueous acidity refer the link:
brainly.com/question/18648828
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Answer: 0.4375 mols of solute
Explanation:
The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is 
. Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.
[multiply both sides by 1.75 L]
There are 0.4375 mols of solute.
