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sergiy2304 [10]
2 years ago
11

a sample of an unknown metal has a mass of 21.6g and volume of an 8.00cm3 calculate the density of the unknown metal

Chemistry
1 answer:
Strike441 [17]2 years ago
4 0

Answer:

<h2>2.70 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{21.6}{8}  \\  = 2.7

We have the final answer as

<h3>2.70 g/cm³</h3>

Hope this helps you

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I think this is it.

Explanation:

As all the mass of other molecules are given and we have to find the mass of hydrogen so total subtracted by carbon and oxygen.

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The compound that contains a radical is called NaOH.

Explanation:

Radical, also called Free Radical, in chemistry, a fragment that contains at trivial one unpaired electron. Most molecules include even numbers of electrons, and the covalent chemical bonds including the atoms commonly within a molecule normally consist of pairs of electrons jointly shared by the atoms combined by the bond.

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H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

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Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
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  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
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Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

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I NEED HELP PLEASE ASAP! BRAINLIEST :)
Keith_Richards [23]

Answer:

6. d

7.c

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9.b

Explanation:

For 6, the answers are not particularly close to 100, and they are not clustered much. For 7, the answers are all clustered very close to 100. For 8, the answers are clustered closely, but not close to 100. For 9, the answers are close to 100, but not clustered very tightly. Hope this helps!

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