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3241004551 [841]

3 years ago

8

You are considering purchasing a compact washing machine, and you have the following information: The Energy Guide claims an est

imated yearly electricity use of 350 kW-hrs, based on 8 loads of laundry being washed per week. The Energy Guide claims an estimated yearly operating cost of $38. This estimate is based on $0.1065 per kW-hr, and eight loads of laundry being washed per week. Local electricity costs $0.086 per kW-hr. You wash four loads of laundry per week. Based on this information, first calculate the energy that would be used by this compact washing machine in a year. Then calculate the yearly energy cost. a. $3.27 b. $19.00 c. $15.34 d. $178.40

1 answer:

RSB [31]3 years ago

8 0

Answer: $15.34

Explanation: see image below

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Rehoboam reigned in Jerusalem over the tribes of

<em>judah </em><em>and </em><em>benjiman</em>

8 0

3 years ago

A small submarine has a triangular stabilizing fin on its stern. The fin is 1 ft tall and 2 ft long. The water temperature where

Arturiano [62]

Answer:

$\mathbf{F_D \approx 1.071 \ lbf}$

Explanation:

Given that:

The height of a triangular stabilizing fin on its stern is 1 ft tall

and it length is 2 ft long.

Temperature = 60 °F

The objective is to determine the drag on the fin when the submarine is traveling at a speed of 2.5 ft/s.

From these information given; we can have a diagrammatic representation describing how the triangular stabilizing fin looks like as we resolve them into horizontal and vertical component.

The diagram can be found in the attached file below.

If we recall ,we know that;

Kinematic viscosity v = $1.2075 \times 10^{-5} \ ft^2/s$

the density of water ρ = 62.36 lb /ft³

$Re_{max} = \dfrac{Ux}{v}$

$Re_{max} = \dfrac{2.5 \ ft/s \times 2 \ ft }{1.2075 \times 10 ^{-5} \ ft^2/s}$

$Re_{max} = 414078.6749$

$Re_{max} = 4.14 \times 10^5$ which is less than < 5.0 × 10⁵

Now; For laminar flow; the drag on the fin when the submarine is traveling at 2.5 ft/s can be determined by using the expression:

$dF_D = (\dfrac{0.664 \times \rho \times U^2 (2-x) dy}{\sqrt{Re_x}})^2$

where;

$(2-x) dy$ = strip area

$Re_x = \dfrac{2.5(2-x)}{1.2075 \times 10 ^{-5}}$

Therefore;

$dF_D = (\dfrac{0.664 \times 62.36 \times 2.5^2 (2-x) dy}{\sqrt{ \dfrac{2.5(2-x)}{1.2075 \times 10 ^{-5}}}})$

$dF_D = 1.136 \times(2-x)^{1/2} \ dy$

Let note that y = 0.5x from what we have in the diagram,

so , x = y/0.5

By applying the rule of integration on both sides, we have:

$\int\limits \ dF_D = \int\limits^1_0 \ 1.136 \times(2-\dfrac{y}{0.5})^{1/2} \ dy$

$\int\limits \ dF_D = \int\limits^1_0 \ 1.136 \times(2-2y)^{1/2} \ dy$

Let U = (2-2y)

-2dy = du

dy = -du/2

$F_D = \int\limits^0_2 \ 1.136 \times(U)^{1/2} \ \dfrac{du}{-2}$

$F_D = - \dfrac{1.136}{2} \int\limits^0_2 \ U^{1/2} \ du$

$F_D = -0.568 [ \dfrac{\frac{1}{2}U^{ \frac{1}{2}+1 } }{\frac{1}{2}+1}]^0__2$

$F_D = -0.568 [ \dfrac{2}{3}U^{\frac{3}{2} } ] ^0__2$

$F_D = -0.568 [0 - \dfrac{2}{3}(2)^{\frac{3}{2} } ]$

$F_D = -0.568 [- \dfrac{2}{3} (2.828427125)} ]$

$F_D = 1.071031071 \ lbf$

$\mathbf{F_D \approx 1.071 \ lbf}$

8 0

3 years ago

The arrival rate at a parking lot is 6 veh.min. Vehicles start arriving at 6:00PM and when the queue reaches 36 vehicles, servic

seraphim [82]

Answer:

Departure rate = 7.65 vehicle/min

Explanation:

See the attached file for the calculation.

5 0

3 years ago

Help I will brainliest

ValentinkaMS [17]

Answer:

hacking?

Explanation:

jsd

3 0

3 years ago

Which of the following material properties varies with temperature? a)- density b)- viscosity c)- electrical resistance d)- all

Reil [10]

Answer:

(d) all of the above

Explanation:

Effect on the density of temperature: If we increase the temperature of any room then particles of the room moves and to and fro and so density is decrease

Effect on the viscosity of temperature : viscosity is inversely proportional to the temperature if we increase the temperature viscosity decreases and if we decrease the temperature viscosity increases.

Effect on the resistance of temperature : For metals if we increase the temperature then resistance increases and for semiconductor if we increase the temperature resistance decreases

So from above discussion all the parameter depends on the temperature so option (d( will be the correct option

6 0

3 years ago