You are considering purchasing a compact washing machine, and you have the following information: The Energy Guide claims an est
imated yearly electricity use of 350 kW-hrs, based on 8 loads of laundry being washed per week. The Energy Guide claims an estimated yearly operating cost of $38. This estimate is based on $0.1065 per kW-hr, and eight loads of laundry being washed per week. Local electricity costs $0.086 per kW-hr. You wash four loads of laundry per week. Based on this information, first calculate the energy that would be used by this compact washing machine in a year. Then calculate the yearly energy cost. a. $3.27 b. $19.00 c. $15.34 d. $178.40
1 answer:
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Answer:
Explanation:
Lets take the numerator of the fraction to be = x
So the denominator of the fraction is 4 more than the numerator = x+4
The fraction is ;
Now add 4 to the numerator and add 7 to the denominator as;
This new fraction is equal to 1 half =1/2
write the equation as;
perform cross-product
2(x+4 )=1( x+11 )
2x+8 = x + 11
2x-x = 11-8
x=3
The original fraction is;
Answer:
P=361.91 KN
Explanation:
given data:
brackets and head of the screw are made of material with T_fail=120 Mpa
safety factor is F.S=2.5
maximum value of force P=??
<em>solution:</em>
to find the shear stress
T_allow=T_fail/F.S
=120 Mpa/2.5
=48 Mpa
we know that,
V=P
<u>Area for shear head:</u>
A(head)=π×d×t
=π×0.04×0.075
=0.003×πm^2
<u>Area for plate:</u>
A(plate)=π×d×t
=π×0.08×0.03
=0.0024×πm^2
now we have to find shear stress for both head and plate
<u>For head:</u>
T_allow=V/A(head)
48 Mpa=P/0.003×π ..(V=P)
P =48 Mpa×0.003×π
=452.16 KN
<u>For plate:</u>
T_allow=V/A(plate)
48 Mpa=P/0.0024×π ..(V=P)
P =48 Mpa×0.0024×π
=361.91 KN
the boundary load is obtained as the minimum value of force P for all three cases. so the solution is
P=361.91 KN
note:
find the attached pic
