What is stress corrosion cracking?

What are the approximate solutions to the quadratic function x^2+6x-4=0

posledela

Solve the equation for
x
x
by finding
a
a
,
b
b
, and
c
c
of the quadratic then applying the quadratic formula.
Exact Form:
x
=
3
±
√
13
x
=
3
±
13
Decimal Form:
x
=
6.60555127
…
,
−
0.60555127
…
x
=
6.60555127
…
,
-
0.60555127
…

6 0

3 years ago

What is the output of the following program fragment. Choose appropriate data-types of variables to match output.

Alexxx [7]

Answer:

1

Explanation:

Given :

i=7;j=8;k=9;

printf(“%d”,(i+10)%k/j);

The printf function only displays the result

%d - is used for the display format

However, the actual calculation is in the expression: (i+10)%k/j

Given the variables :

i = 7 ;

j = 8 ;

k = 9 ;

(i + 10) = (7 + 10) = 17

(i + 10) % k = 17 % 9

% = remainder value after division

17 % 9 = (17 / 9) = 1 remainder 8

17 % 9 = 8

Hence,

(i + 10) % k = 8

(i + 10) % k / j

j = 8

8 / 8

= 1

3 0

3 years ago

R1 = 2.2 kΩ R2 = 4.7 kΩ C = 0.1 F Vdc = +5 V Vac = 5 V peak f = 1 kHz A. Use superposition to calculate the dc voltage at point

horrorfan [7]

Answer:

See attachments for step by step procedure into getting answers.

Explanation:

Given that;

R1 = 2.2 kΩ R2 = 4.7 kΩ C = 0.1 F Vdc = +5 V Vac = 5 V peak f = 1 kHz A. Use superposition to calculate the dc voltage at point X: Vdc = ______

See attacent for complete solving

4 0

3 years ago

A 650-kN column load is supported on a 1.5 m square, 0.5 m deep spread footing. The soil below is a well-graded, normally consol

insens350 [35]

<u>Explanation:</u>

Determine the weight of footing

$W_{f}=\gamma(L)(B)(D)$

Where $W_{f}$ is the weight of footing, γ is the unit weight of concrete, L is the length of footing is the width of footing, and D is the depth of footing

Substitute $2 m \text { for } L, 1.5 m \text { for } B, 0.5 m \text { for } D \text { and } 23.6 kN / m ^{3}$ for γ in the equation

$\begin{aligned}W_{f} &=\left(23.6 kN / m ^{3}\right)(2 m )(1.5 m )(0.5 m ) \\&=35.4 kN\end{aligned}$

Therefore, the weight of the footing is 35.4 kN

Determine the initial vertical effective stress.

$\sigma_{z p}^{\prime}=\gamma(D+B)-u$

Here, $\sigma_{z^{p}}^{\prime}$ is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.

Substitute $18 kN / m ^{3} \text { for } \gamma, 1.5 m \text { for } B, 0.5 m \text { for } D \text { and } 0$ for u in the equation

$\begin{aligned}\sigma_{z p}^{\prime} &=\left(18 kN / m ^{3}\right)(1.5+0.5) m -0 \\&=36 kPa\end{aligned}$

Therefore, the initial vertical stress is 36 kPa

Determine the vertical effective stress.

$\sigma_{z D}^{\prime}=\gamma D$

Here, $\sigma_{z^{p}}^{\prime}$ is initial vertical stress at a depth below ground surface γ is the unit weight of soil, D is depth and u is pore water pressure.

Substitute $18 kN / m ^{3}\) for $\gamma, 0.5 m$ for $D$ and 0 for \(u$ in the equation.

$\begin{aligned}\sigma_{z b}^{\prime} &=\left(18 kN / m ^{3}\right)(0.5 m )-0 \\&=9 kPa\end{aligned}$

Therefore, the vertical stress at a depth below the ground surface is

9 kPa

Determine the influence factor at the midpoint of soil layer,

$I_{e p}=0.5+0.1 \sqrt{\frac{q-\sigma_{s 0}^{\prime}}{\sigma_{z p}^{\prime}}}$

Here $I_{e p}$ is the influence factor at the midpoint of soil layer $\sigma_{z^{p}}^{\prime}$ is initial vertical stress, $\sigma_{z^{p}}^{\prime}$ is vertical effective stress, and $Q$ is bearing pressure

Substitute $36 kPa for $\sigma_{z p}^{\prime}, 228.47$ kPa for $q,$ and 9 kPa for $\sigma_{z D}^{\prime}$$ in the equation $\begin{aligned}I_{\epsilon P} &=0.5+0.1 \sqrt{\frac{228.47 kPa -9 kPa }{36 kPa }} \\&=0.75\end{aligned}$

Therefore the influence factor at the midpoint of the soil layer is 0.693

6 0

4 years ago

(Blank) welding involves manual welding with equipment anomalously controls one or more of the windy conditions while (blank) we

shepuryov [24]

Answer:

D.

Explanation:

In automated welding, defined as “welding with equipment that requires only occasional or no observation of the weld, and no manual adjustment of the equipment controls,” the welder's involvement is limited to activating the machine to initiate the welding cycle and observing the weld on an intermittent basis.

8 0

3 years ago