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anyanavicka [17]
3 years ago
11

The input and output signals of a system is related by the following equation: fraction numerator d squared y over denominator d

t squared end fraction plus sin (3 y )fraction numerator d y over denominator d t end fraction plus y equals t fraction numerator d f over denominator d t end fraction plus f. Then, the system is:
Engineering
1 answer:
Colt1911 [192]3 years ago
5 0

Answer:

Explanation:

The given equation is :

\frac{d^{2}y }{dx^{2} } + sin(3y) \frac{dy}{dt} + y = t\frac{df}{dt} + f

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Which of these fuel injection systems operates with fuel injectors located only in the intake manifold near each intake
Stella [2.4K]

Answer:

C. Multipoint fuel injection

Explanation:

A fuel injection system can be defined as a system found in the engine of most automobile cars, used for the supply of a precise amount of fuel or fuel-air mixture to the cylinders in an internal combustion engine through the use of an injector.

There are different types of fuel injection system and these includes;

I. Central-point injection.

II. Throttle (single point) body injection.

III. Gasoline direct injection.

IV. Multipoint (port) fuel injection.

Multipoint fuel injection is a type of fuel injection system that operates with fuel injectors located only in the intake manifold near each intake valve and sprays fuel toward the valve. As a result, it allows for the supply of a precise amount of fuel and as such creating a better air-fuel ratio for automobile cars.

8 0
2 years ago
(Specific weight) A 1-ft-diameter cylindrical tank that is 5 ft long weighs 125 lb and is filled with a liquid having a specific
lina2011 [118]

Answer:

The answer to the question is 514.17 lbf

Explanation:

Volume of cylindrical tank = πr²h = 3.92699 ft³

Weight of tank = 125 lb

Specific weight of content = 66.4 lb/ft³

Mass of content =  66.4×3.92699 = 260.752 lb

Total mass = 260.752 + 125 = 385.75 lb = 174.97 kg

=Weight = mass * acceleration = 174.97 *9.81 = 1716.497 N

To have an acceleration of 10.7 ft/s² = 3.261 m/s²

we have F = m*a = 174.97*(9.81+3.261) = 2287.15 N = 514.17 lbf

5 0
3 years ago
The performance of a heat pump degrades (i.e., its COP decreases) as the temperature of the heat source decreases. This makes us
vfiekz [6]

Answer:

COP_max = 18.69

Explanation:

We are given;

Heated space temperature; T_H = 26°C = 273K + 26 = 299K

Temperature at which heat is extracted; T_L = 10°C = 273 + 10 = 283K

Now the Coefficient of performance (COP) of a heat pump will be a maximum when the heat pump operates in a reversible manner. The COP of a reversible heat pump depends on the temperature limits in the cycle only and is determined by the formula;

COP_max = 1/(1 - (T_L/T_H))

Thus,

COP_max = 1/(1 - (283/299))

COP_max = 1/(1 - 0.9465)

COP_max = 1/0.0535 = 18.69

7 0
3 years ago
Ethan is an engineer who is trying to create a totally quiet fluid power system. Which part of the fluid power system will he ne
creativ13 [48]

Answer:

C: compressor

Explanation:

As it states in the text, Unfortunately, the pump or compressor in a fluid power system is often noisy and heavy. This aspect of the fluid power system is a critical area of interest for engineers and scientists who seek to improve fluid power.

3 0
3 years ago
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Please LIKE & SHARE to keep our generators available!
ehidna [41]

Answer:

Is this a questions

Explanation:

please I don't understand

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3 years ago
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