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hoa [83]
4 years ago
15

A sound wave travels at 330 m/sec and has a wavelength of 2 meters. Calculate its frequency and period.

Physics
2 answers:
EleoNora [17]4 years ago
6 0

Answer:

660

Explanation:

Zanzabum4 years ago
3 0
Frequency=velocity/wavelength 330/2=165 hertz period=1/frequency=1/165 second
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Four copper wires of equal length are connected in series. Their cross-sectional areas are 0.7 cm2 , 2.5 cm2 , 2.2 cm2 , and 3 c
Travka [436]

Answer:

22.1 V

Explanation:

We are given that

A_1=0.7 cm^2=0.7\times 10^{-4} m^2

A_2=2.5 cm^2=2.5\times 10^{-4} m^2

A_3=2.2 cm^2=2.2\times 10^{-4} m^2

A_4=3 cm^2=3\times 10^{-4} m^2

Using 1cm^2=10^{-4} m^2

We know that

R=\frac{\rho l}{A}

In series

R=R_1+R_2+R_3+R_4

R=\frac{\rho l}{A_1}+\frac{\rho l}{A_2}+\frac{\rho l}{A_3}+\frac{\rho l}{A_4}

R=\frac{\rho l}{\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4}}

Substitute the values

R=\rho A(\frac{1}{0.7\times 10^{-4}}+\frac{1}{2.5\times 10^{-4}}+\frac{1}{2.2\times 10^{-4}}+\frac{1}{3\times 10^{-4}})

R=\rho l(2.62\times 10^4)

V=145 V

I=\frac{V}{R}=\frac{145}{\rho l(2.62\times 10^4)}

Voltage across the 2.5 square cm wire=IR=I\times \frac{\rho l}{A_2}

Voltage across the 2.5 square cm wire=\frac{145}{\rho l(2.62\times 10^4)}\times \frac{\rho l}{2.5\times 10^{-4}}=22.1 V

Voltage across the 2.5 square cm wire=22.1 V

6 0
3 years ago
Here's a question from ~ [ AIEEE 2002 ]
lyudmila [28]
  • r=150m
  • coefficient of friction=\mu=0.6

As car is avoid skidding

\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg

  • Cancel m

\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g

\\ \sf\hookrightarrow v^2=\mu rg

\\ \sf\hookrightarrow v^2=0.6(10)(150)

\\ \sf\hookrightarrow v^2=60(150)

\\ \sf\hookrightarrow v^2=900

\\ \sf\hookrightarrow v=30ms^{-1}

Done

7 0
2 years ago
Read 2 more answers
Which characteristics can be used to differentiate star systems? Select three options.
anyanavicka [17]

Answer:

1,3and4 just did and got correct

Explanation:

5 0
2 years ago
The diagram shows a transformer. Based on the diagram the voltage at the second winding is ____ v
Karolina [17]

Answer:

60V

Explanation:

240V/12 loops = 20 volts per loop.

20 * 3 = 60 volts  

3 0
3 years ago
Read 2 more answers
Two people push on a boulder to try to move it. The mass of the boulder is 825 kg. One person pushes north with a force of 64 N.
stira [4]

Answer:

0.09 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

From the question, expression for acceleration is given as

F' = ma  

Using Pythagoras Theory,

√(F₁²+F₂²) = ma................... Equation 1

Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.

make a the subject of the equation

a = √(F₁²+F₂²) /m................ Equation 2

Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,

Substitute into equation 2

a = [√(64²+38²)]/825

a = {√(5540)}/825

a = 74.43/825

a = 0.09 m/s²

4 0
3 years ago
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