Answer:
We have that θ is the angle that makes the normal of the loop and the direction of the magnetic field.
This means that if θ = 0°, the plane in which the loop of wire lies is totally perpendicular to the magnetic field. (or the face of the loop points in the same direction than the field)
Now, the magnetic flux can be calculated as:
Where dA is the differential of area, and we have a dot product, then we have:
B.dA = B*Acos(θ)ds
ds is a differential of surface.
Now, the flux will be maximum when cos(θ) is also a maximum.
And the maximum of the cosine is:
Cos(0°) = 1.
decreasing until cos(90°) = 0
Now, the options given are:
30°, 45°, 60° and 90°.
Then in this range, the maximum flux will occur at the angle closer to 0°, then the correct option is θ = 30°
Answer:
The scope of physics is quite vast and covers an enormous range of magnitude of physical quantities like mass, length, time, energy etc.
The scope is divided into two sections, where on one side it studies about phenomena at a very small microscopic level involving and analyzing electrons, protons, and neutrons.
Answer:
50 m in 10 sec….divide 50 by 10 to convert to metres per second = 5 m/s. Then multiply by 3.6 (3600 seconds in an hour divided by 1000) to convert to kilometres per hour =18 m/s. To convert to mph divide by 1.609 =11.18 mph.
Explanation:
Answer:
distance between school and home is 21 miles
Explanation:
given data
in rush hour speed s1 = 28 mph
less traffic speed s2 = 42 mph
time t = 1 hr 15 min = 1.25 hr
to find out
distance d
solution
we consider here distance home to school is d and t1 time to reach at school
we get here distance equation when we go home to school that is
distance = 28 × t1 .......................1
and when we go school to home distance will be
distance = 42 × ( t - t1 )
distance = 42 × ( 1.25 - t1 ) ...................2
so from equation 1 and 2
28 × t1 = 42 × ( 1.25 - t1 )
t1 = 0.75
so
from equation 1
distance = 28 × t1
distance = 28 × 0.75
distance = 21 miles
Answer:
The charge flows in coulombs is
Explanation:
The current magnitude of current is given by the resistance and the induced Emf as:
, 
, 
, 
Ω
,
Replacing :
