Answer:
57.1 km/hr
Explanation:
To find the average speed you take the total distance divided by the total elapsed time.
So, the total distance is 140 + 60 = 200
the total elapsed time is found by taking 140/70=2 and 60/40=1.5
2+1.5=3.5
The plug the numbers into the equation,
200/3.5=57.1
Answer
-The magnitude of acceleration during the fall is greater
W = 980N. The weight of an object of 100Kg in the Earth is 980N.
The weight is a measure of the gravitational force acting on an object, the weight is equivalent to the force exerted by a body on a point of support, caused by the action of the local gravitational field on the mass of the body.
it can be defined as the product of mass by the acceleration of gravity, w = mg. Since weight is a force, its unit is the Newton N.
If the mass of an object on earth is 100 kg, then is weight is:
W = (100Kg)(9.8m/s²) = 980N.
Answer:
kicking ball and throwing stone
Answer:
Rmax = 3.4 10⁶ m
Explanation:
For this exercise we will use the concept of energy
Initial. On the surface of the luma
Em₀ = K + U
Em₀ = ½ m v² - G m M / R_moon
Final. At the furthest point
Emf = U
Emf = - g m M / R_max
Em₀ = Emf
½ m v² - G m M / R_moon = - G m M / R_max
½ v² + G M (-1 / R_moon + 1 / R_max) = 0 (1)
Let's use the fact that tells us that the speed of the rocket is equal to the speed of a satellite that rotates around the moon near the surface, let's use Newton's second law
F = m a
Acceleration is centripetal
a = v² / r
r= R_moon
G m M / R_moon² = m v² / R_mon
G M / R_moon = v²
We substitute in 1
½ G M / R_moon + G M (1 / R_max - 1 / R_moon) = 0
1 / R_max = 1 / R_moon (1- ½)
R_max = R_moon 2
Rmax = 2 1700 103
Rmax = 3.4 10⁶ m
