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lorasvet [3.4K]
2 years ago
15

Help sdfghrthfbfdve aahhhhhhhh

Chemistry
1 answer:
nirvana33 [79]2 years ago
5 0
I believe the answer is C !
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2. Water can be understood as both yin and yang. Challenge: how many ways can you explain why ?
GuDViN [60]

Water can be understood as both yin and yang. The number of ways Yin and Yang can be explained is in numerous ways.

Yin and Yang explain how to exist in harmony and in balance with nature. Yin and Yang are not distinct entities, but rather two extremes of a spectrum. Everything Yin includes a trace of Yang. Also, everything Yang contains a trace of Yin. They are always in connection with one another.

The yin is the physical aspect of nature and the yang is the forces surrounding these physical aspects.

Some of the ways in which Yin and Yang can be explained are as follows:

  • Yin and Yang can be explained from the water, whereby the water is the Yin while the wind carrying the water waves is known as the Yang.

  • In the body, the Yin shows the anatomy and structure of the body while the Yang explains the psychological functioning of the body.

Disruption in either Yin or Yang can cause an imbalance in nature.

Therefore, we can conclude that the number of ways in which we can explain the Yin and the Yang is numerous.

Learn more about nature here:

brainly.com/question/23250589?referrer=searchResults

5 0
2 years ago
HELP ME PLEASE !!! I.D.K WHAT TO DO :((( Will mark brainliest please !!
Svetradugi [14.3K]
I’m sorry but where’s the worksheet lol......
7 0
3 years ago
Read 2 more answers
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

6 0
3 years ago
What force is needed to accelerate a truck with mass 2,000 kg at a rate of 5.0
Makovka662 [10]

Answer:

D

Explanation:

F=ma \\\\F=2000\cdot 5=10,000N

Hope this helps!

6 0
2 years ago
Fill in the blank for a stoichiometric iso-octane air mixture. C8H18 + ____ (O2+3.76N2)
kati45 [8]

Answer: Option 12.5 is the correct answer.

Explanation:

The given reaction is as follows.

           C_{8}H_{18} + x(O_{2} + 3.76N_{2}) \rightarrow Products

As it is a combustion reaction so, nitrogen will not take part in it and hence, it will remain the same on both sides of the reaction.

Also, it is known that in a combustion reaction oxygen reacts with a hydrocarbon and results in the formation of carbon dioxide and water. Therefore, for the above reaction we write the complete reaction equation as follows.

             C_{8}H_{18} + x(O_{2} + 3.76N_{2}) \rightarrow CO_{2} + H_{2}O + 3.76 N_{2}

or,         C_{8}H_{18} + xO_{2} \rightarrow CO_{2} + H_{2}O as nitrogen is not taking part in the reaction.

Number of atoms on reactant side are as follows.

C = 8

H = 18

O = 2

Number of atoms on product side are as follows.

C = 1

O = 3

H = 2

Therefore, to balance this equation we multiply oxygen on reactant side by 12.5. Also, we multiply carbondioxide by 8 and water by 9 on product side. Hence, the complete balanced chemical equation is as follows.

          C_{8}H_{18} + 12.5O_{2} \rightarrow 8CO_{2} + 9H_{2}O

8 0
3 years ago
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