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lorasvet [3.4K]
2 years ago
15

Help sdfghrthfbfdve aahhhhhhhh

Chemistry
1 answer:
nirvana33 [79]2 years ago
5 0
I believe the answer is C !
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Compare your predicted ranking of the objects’ volumes with their final ranking based on their measurements. What are the advant
Schach [20]

Answer:

Since its data sample can be quantified using fixed numerical parameters, quantitative observation yields more accurate results than qualitative observation and it is suitable for statistical investigations.

Explanation:

8 0
3 years ago
A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

Substitute the values into the formula:

​p = \frac{16.59 g}{5.81 mL} \\   = 2.8554 g/mL

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

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2 years ago
Use the information in the table to describe the temperature-vs.-time diagrams.
Paha777 [63]
I think answer should be the last option I hope this helps let me know if it’s correct thanks
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3 years ago
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An acid with the general formula RCOOH is used to make a 0.10 M solution in water. The pH of this acid solution is measured as 3
Sati [7]

Answer:

0.159 \%

Explanation:

The acid will dissociate according to the reaction shown below:-

RCOOH + H_2O\rightleftharpoons RCOO^- + H_3O^+

Given that, pH=3.8

The concentration of can be determined from the expression fo pH as:-

pH = - log [H^+]

3.8  = - log [H^+]

[H^+] = 1.59\times 10^{-4}\ M

The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-

\% \ dissociation=\frac{1.59\times 10^{-4}}{0.10}\times 100=0.159\ \%

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2 years ago
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DiKsa [7]

Answer:

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Explanation:

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