1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
steposvetlana [31]
3 years ago
12

A person raises a box with a weight of 50 newtons by 0.5 meter. How much work does the person do in this action?(1 point)

Physics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

25J

Explanation:

Given parameters:

Weight of a box  = 50N

Height  = 0.5m

Unknown:

Work done  = ?

Solution:

Work done is the product of the force applied to move a load through a distance.

 So;

    Work done  = weight x height  = 50 x 0.5  = 25J

You might be interested in
¿Por qué en algunas partes el agua tiene mayor presión?
Phantasy [73]
Cuando la presión aumenta en el agua, disminuye el punto de fusión del hielo. Ósea esta a temperatura muy alta.


Espero que esto te ayude y no me haya confundido
7 0
3 years ago
A parallel plate air capacitor has a capacitance of 10 to the power -9. What potential difference is required for a charge of 5×
Maurinko [17]

The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

<h3>What is the energy in a capacitor?</h3>

The energy stored in a capacitor is an electrostatic potential energy.

It is related to the charge(Q) and voltage (V) between the capacitor plates.

It is represented as 'U'.

<h3>How to determine the potential difference</h3>

Formula:

Potential difference, V is the ratio of the charge to the capacitance of a capacitor.

It is calculated using:

V = Q ÷ C

Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9

Substitute the values into the equation

Potential difference, V = 5 × 10∧-5 ÷  10∧-9 = 5 × 10∧4 volts

<h3>How to determine the energy stored</h3>

Formula:

Energy, U = 1 ÷ 2 (QV)

Where Q= charge and V = potential difference across the capacitor

Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)

= 0.5 × 25 × 10∧-1

= 0.5 × 2.5

= 1. 25 Joules

Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules

Learn more about capacitance here:

brainly.com/question/14883923

#SPJ1

6 0
2 years ago
A 160.-kilogram space vehicle is traveling along a
mario62 [17]

If the object is moving in a straight line at a constant speed, then that's
the definition of zero acceleration.  It can only happen when the sum of
all forces (the 'net' force) on the object is zero.

And it doesn't matter what the object's mass is.  That argument is true
for specks of dust, battleships, rocks, stars, rock-stars, planets, and
everything in between.

4 0
3 years ago
As shown above an adhesive has been applied to contacting faces of two blocks so that the blocks interact with an adhesive force
rusak2 [61]

The magnitude of the adhesive force allows the top block to remain

attached to the bottom when the blocks and the wire are balanced.

The option that must be true is; \mathbf{W_{bottom} = F_{adhesion}}

Reason:

The tension exerted by the wire attached to the top block = T

Magnitude of the adhesive = F_{adhesion}

Weight of the top block = W_{top}

Weight of the bottom block = W_{bottom}

Given that with the exertion of the tension, the two blocks remain at rest, we have;

  • T =  W_{top} + W_{bottom}

The adhesive causes the bottom block to remain attached to the top block, we have;

Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;

The magnitude of the adhesive force = The weight of the bottom block

Therefore;

  • W_{bottom} = F_{adhesion}

Learn more here:

brainly.com/question/18907970

8 0
3 years ago
Two wires with the same resistance have the same diameter but different lengths. If wire 1 has length L 1 and wire 2 has length
SVEN [57.7K]

Answer with Explanation:

We are given that

Length of wire 1=L_1

Length of wire 2=L_2

Resistivity of copper wire=\rho_1=1.7\times 10^{-5}\Omega-m

Resistivity of aluminum wire=\rho_2=2.82\times 10^{-5}\Omega-m

Wire 1=Copper wire

Wire 2=Aluminum wire

Diameter of both wires are same and resistance of both wires are also same.

We know that

Resistance =\frac{\rho l}{A}

When diameter of wires are same then their cross section area are also same .

l=\frac{RA}{\rho}

When resistance and area are same then the length of wire depend upon the resistivity of wire .

The length of wire is inversely proportional to resistivity.

When resistivity is greater then the length of wire will be short and when the resistivity  is small then the length of wire will be large.

\rho_1

Therefore, L_1>L_2

Hence, the length of wire 1 (copper wire) is greater than the length of wire 2 (aluminum).

\frac{L_1}{L_2}=\frac{\frac{RA}{1.7\times 10^{-5}}}{\frac{RA}{2.82\times 10^{-5}}}=1.66

L_1=1.66L_2

7 0
3 years ago
Other questions:
  • An airplane travels 500 miles in 2.5 hours. What is the speed of the plane in mi/sec
    6·1 answer
  • What is the momentum of a dog of mass 14 kg that is running east with a
    12·1 answer
  • Which type of graph would be best for showing the percentage of people in a family with different jobs? A. Circle graph B. Scatt
    15·1 answer
  • Which vector has a y-component with a length of 4?
    15·1 answer
  • What causes lightning?​
    5·2 answers
  • (0.50kg)(6.0mls)+(1.00kg)(-12.00mls)
    14·1 answer
  • What is the net force on this object A: 0 newtons b: 200 newtons c:400 newtons D:600 newtons
    9·1 answer
  • HELP PLEASE TY!
    15·2 answers
  • Lightning always follows
    6·2 answers
  • What is the magnetic field due to a very very long wire with current A at a perpendicular distance 0.30000000000000004 m away fr
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!