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anygoal [31]
4 years ago
11

A submarine can detect an approaching enemy submarine using sonar. If a stationary submerged submarine emits a 100kHz tone and r

eceives a tone Doppler shifted by 200Hz, calculate the speed of the enemy submarine if the speed of sound in salt water is 1,482m/s. Note: Because the echo is off of a moving object, the moving object amplifies the Doppler effect by a factor of 2! Therefore, the speed must be cut in half. A. 1.0m/s B. 1.5m/s C.2.2m/s OD.3.3m/s E. 4.4m/s
Physics
1 answer:
kotegsom [21]4 years ago
7 0

Answer:

B) 1.5 m/s

Explanation:

The apparent frequency will be enhanced due to Doppler effect

If f be the apparent frequency , F be the real frequency  , V be the velocity of sound and v be the velocity of approaching submarine then f is given by

f = F \frac{V+v}{V-v}\\

\frac{f}{F} =\frac{V+v}{V-v}\\  

\frac{f}{F}-1  =\frac{V+v}{V-v}-1\\

\Delta f = \frac{2vf}{V-v}\\

200=\frac{2\times v\times 100\times 1000}{1482-v}\\  

v=1.48 m/s

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3 years ago
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You are asked to calculate how long a new battery will last on a flashlight when the flashlight is turned on. how long should yo
valina [46]

Answer:

           Depends on the capacity of battery. Mostly our phones flashlight can be used up to 8 to 10hrs continuosly

Explanation:

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5 0
2 years ago
Select all the correct answers.
velikii [3]
Soda and metal, so b and c :)
8 0
3 years ago
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A wave on a string has a wavelength of 0.90 m at a frequency of 600 Hz. If a new wave at a frequency of 300 Hz is established in
kobusy [5.1K]

Answer:

 λ₂ = 1.8 m

Explanation:

given,

wavelength of the string 1 = 0.90 m

frequency of the string 1 = 600 Hz

wavelength of string 2 = ?

frequency of the string 2 = 300 Hz

we now,

f\ \alpha\ \dfrac{1}{\lambda}

now,

\dfrac{f_1}{f_2}=\dfrac{\lambda_2}{\lambda_1}

\dfrac{600}{300}=\dfrac{\lambda_2}{0.9}

λ₂ = 2 x 0.9

 λ₂ = 1.8 m

Hence, the wavelength of the second string is equal to  λ₂ = 1.8 m

8 0
3 years ago
A shark swims around his circular pool. What is the centripetal force of the 681kg shark if the pool has a diameter of 14m and i
blsea [12.9K]
<span>29 Newtons
   Centripetal force is modeled by the equation:
  F = MV^2/R where
 F = force
 M = Mass
 V = Velocity
 R = Radius

   I will assume the shark is swimming in a circle with a radius of 14 m / 2 = 7 m. The actual radius will be smaller, but I'll assume that the question is simply poorly worded. So we need to calculate the velocity of the shark. The circumference of the circle is pi*14m = 43.98229715 m. And since velocity is defined as distance over time, we have a velocity of 43.98229715 m / 80 s = 0.549778714 m/s.

   Now substitute the known values into the equation for centripetal force.
 F = MV^2/R
 F = 681 kg * ( 0.549778714 m/s)^2 / 7m
 F = 681 kg * 0.302256635 m^2/s^2 / 7m
 F = 205.8367683 kg*m^2/s^2 / 7m
 F = 29.40525261 kg*m/s^2
 F = 29.40525261 N
   Rounding to 2 significant figures gives a force of 29 Newtons.</span>
5 0
4 years ago
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