Answer:
Area = 20 m²
Explanation:
Given the following data;
Force = 2500 N
Pressure = 125 Pa
To find the area on which it rest;
Mathematically, pressure is given by the formula;
Making area the subject of formula, we have;
Substituting into the formula, we have;
Area = 20 m²
It will move in the direction of applied force following the law of newton that is an object is stationary until an external force is applied then it moves in direction of force
Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
![v=\omega\times \sqrt{[ A^2 - y^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20A%5E2%20-%20y%5E2%20%5D%7D)
![v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20%7B0.06%7D%5E2%20-%20%7B0.045%7D%5E2%20%5D%7D)
<u>Velocity = 0.4762 m/s</u>
Answer:
a) E = 8628.23 N/C
b) E = 7489.785 N/C
Explanation:
a) Given
R = 5.00 cm = 0.05 m
Q = 3.00 nC = 3*10⁻⁹ C
ε₀ = 8.854*10⁻¹² C²/(N*m²)
r = 4.00 cm = 0.04 m
We can apply the equation
E = Qenc/(ε₀*A) (i)
where
Qenc = (Vr/V)*Q
If Vr = (4/3)*π*r³ and V = (4/3)*π*R³
Vr/V = ((4/3)*π*r³)/((4/3)*π*R³) = r³/R³
then
Qenc = (r³/R³)*Q = ((0.04 m)³/(0.05 m)³)*3*10⁻⁹ C = 1.536*10⁻⁹ C
We get A as follows
A = 4*π*r² = 4*π*(0.04 m)² = 0.02 m²
Using the equation (i)
E = (1.536*10⁻⁹ C)/(8.854*10⁻¹² C²/(N*m²)*0.02 m²)
E = 8628.23 N/C
b) We apply the equation
E = Q/(ε₀*A) (ii)
where
r = 0.06 m
A = 4*π*r² = 4*π*(0.06 m)² = 0.045 m²
Using the equation (ii)
E = (3*10⁻⁹ C)/(8.854*10⁻¹² C²/(N*m²)*0.045 m²)
E = 7489.785 N/C
(Lo siento si mi español es malo, no es mi primera lengua
)
1. velocidad media = desplazamiento/tiempo
desplazamiento = 0 porque el athelete vuelve al punto inicial en un círculo
velocidad media = desplazamiento/tiempo = 0/10 = 0
2. la distancia entre A y B es 5 cm porque
a^2 + b^2 = c^2 (el teorema de Pitágoras) así:
rapidez media = distancia/tiempo = 5/5 = 1 cm/s o 0.01 m/s
y yo no se cómo hacer 3-5 :( lo siento
3. Creo que es dos triángulo
s AB y CD menos la línea de fondo
5. Creo que es E + F porque B y D b y d cancelarse el uno al otro y C y C tambien pero no lo sé con seguridad.
