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4 years ago

Why do the planets appear in different locations in the night sky while the pattern of stars in a constellation stays the same?

2 answers:

8 0

Planets are consantly moving and are relitivly nearby so their movment has a big impact on our veiw o them but stars are far away so it take a huge amount of movement to change our view of them

Goshia [24]4 years ago

7 0

I'm sure you've noticed that an airplane high in the sky, far away
from you, looks like it's moving very slowly. At the same time,
somebody passing you on a skateboard whizzes past you at
high speed. The farther away something is from you, the slower
it appears to move.

The nearest star outside the solar system is almost 32 thousand times
as far away from us as the farthest visible planet (Saturn) is, and all of the
other stars are farther than that.

That's why you have to wait a few thousand years before you notice
that the shape of a constellation has changed.

To put it a slightly different way . . . Everything is in motion. The motion is
more noticeable for nearby things, and less noticeable for farther-away things.
Objects within our solar system are the only ones near enough so that a human
lifetime is a long enough period in which to notice the change in their position.
Even Pluto moves less then 1.5° against the 'background' stars in a whole year.

This all makes me feel small. How about you ?

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4 years ago

A car is moving at 35 mph and comes to a stop in 5 seconds.

amid [387]

Answer:

-10.267

Explanation:

Initial speed > 35 miles per hour

Final speed > 0 miles per hour

Time > 5 seconds

4 0

4 years ago

Read 2 more answers

When Patey Pontoons issued 10% bonds on January 1, 2021, with a face amount of $720,000, the market yield for bonds of similar r

wlad13 [49]

Answer:

Explanation:

Interest is paid semiannually on June 30 and December 31. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.) Required: 1. Determine the price of the bonds on January 1, 2021. 2. Prepare the journal entry to record their issuance by Patey on January 1, 2021. 3. Prepare an amortization schedule that determines interest at the effective rate for each period. 4. Prepare the journal entry to record interest on June 30, 2021. 5. What is the amount related to the bonds that Patey will report in its balance sheet on December 31, 2021? 6. What is the amount related to the bonds that Patey will report in its income statement for the year ended December 31, 2021? (Ignore income taxes.) 7. Prepare the appropriate journal entries at maturity on December 31, 2024. Complete this question by entering your answers in the tabs below. Req 1 Reg 2 Reg 2 Req 3 Req3 Req 4 Req 4 Req 5 and 6 Req 7 Reg 7 Determine the price of the bonds at January 1, 2021. (Round final answers to the nearest whole dollar.) Table values are based on: n = Cash Flow Amount Present Value Interest Principal Price of bonds Req 1 Reg 2 Req 3 Req 4 Req 5 and 6 Req 7 Prepare the journal entry to record their issuance by Patey on January 1, 2021. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list 1 Record the issuance of the bonds on January 1, 2021. Req 1 Req 2 Req3 Req 4 Req 5 and 6 Req 7 Prepare an amortization schedule that determines interest at the effective rate for each period. (Round intermediate calculations and final answers to the nearest whole dollar.) ...................... Semiannual Bond Interest Discount Interest Cash Interest Carrying Value Period-End Expense Amortization 01/01/2021 06/30/2021 12/31/2021 06/30/2022 12/31/2022 06/30/2023 12/31/2023 06/30/2024 12/31/2024 Total Req 1 Req 2 Req 3 Reg 4 Req 5 and 6 Req 7 Prepare the journal entry to record interest on June 30, 2021. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list 1 Record the interest expense on June 30, 2021. Complete this question by entering your answers in the tabs below. Reg 1 Req 2 Req 3 Req 4 Req 5 and 6 Req 7 What is the amount(s) related to the bonds that Patey will report in its balance sheet on December 31, 2021, and income statement for the year ended December 31, 2021? (Ignore income taxes.) (Round intermediate calculations and final answers to the nearest whole dollar.) 5. December 31, 2021 book value 6. Interest expense for 2021 Req 1 Req 2 Req3 Req 4 Req 5 and 6 Req 7 Prepare the appropriate journal entries at maturity on December 31, 2024. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field. Round intermediate calculations and final answers to the nearest whole dollar.) View transaction list X 1 Record the interest expense on December 31, 2024. 2 Record the retirement of the bond at maturity on December 31, 2024.

3 0

3 years ago

Object A has a mass of 100 grams. Object B has a mass of 150 grams. They are both traveling at the same velocity. Which can you

Vladimir [108]

The inertia of an object is proportional to the mass of the object. Inertia is the defined as the force that is needed to stop the moving object. IN this case, the inertia must only depend on the mass. Hence answer is A. Object B has a greater inertia than Object A.

8 0

3 years ago

Read 2 more answers

Solve the given parallel circuit by computing the desired quantities. I1 = amperes I2 = amperes I3 = amperes P1 = watts P2 = wat

Komok [63]

Answer:

1. Current 1 (I1) is 2 A.

2. Current 2 (I2) is 4 A.

3. Current 3 (I3) is 1.3 A.

4. Power 1 (P1) is 48 W.

5. Power 2 (P2) is 96W.

6. Power 3 (P3) is 31.2 W.

7. Total current is 7.3 A.

8. Total power is 175.2 W.

Explanation:

Data obtained from the question include the following:

Voltage (V) = 24 V

Resistance 1 (R1) = 12 Ω

Resistance 2 (R2) = 6 Ω

Resistance 3 (R3) = 18 Ω

1. Determination of the current 1 (I1)

Voltage (V) = 24 V

Resistance 1 (R1) = 12 Ω

Current 1 (I1) =..?

V = I1R1

24 = I1 x 12

Divide both side by 12

I1 = 24/12

I1 = 2 A

Therefore, the current 1 (I1) is 2 A

2. Determination of the current 2 (I2)

Voltage (V) = 24 V

Resistance 2 (R2) = 6 Ω

Current 2 (I2) =..?

V = I2R2

24 = I2 x 6

Divide both side by 6

I2 = 24/6

I2 = 4 A

Therefore, the current 2 (I2) is 4 A

3. Determination of the current 3 (I3)

Voltage (V) = 24 V

Resistance 3 (R3) = 18 Ω

Current 3 (I3) =..?

V = I3R3

24 = I3 x 18

Divide both side by 18

I3 = 24/18

I3 = 1.33 A

Therefore, the current 3 (I3) is 1.3 A.

4. Determination of power 1 (P1)

Voltage (V) = 24 V

Current 1 (I1) = 2 A

Power 1 (P1) =..?

P1 = I1V

P1 = 2 x 24

P1 = 48 W

Therefore, power 1 (P1) is 48 W.

5. Determination of power 2 (P2)

Voltage (V) = 24 V

Current 2 (I2) = 4 A

Power 2 (P2) =..?

P2 = I2V

P2 = 4 x 24

P2 = 96 W

Therefore, power 2 (P2) is 96W.

6. Determination of power 3 (P3)

Voltage (V) = 24 V

Current 3 (I3) = 1.3 A

Power 3 (P3) =..?

P3 = I3V

P3 = 1.3 x 24

P1 = 31.2 W

Therefore, power 3 (P3) is 31.2 W.

7. Determination of the total current

Current 1 (I1) = 2 A.

Current 2 (I2) = 4 A.

Current 3 (I3) = 1.3 A

Total current =.?

Total current = I1 + I2 + I3

Total current = 2 + 4 + 1.3

Total current = 7.3 A

Therefore, the total current is 7.3 A.

8. Determination of the total power.

Power 1 (P1) = 48 W.

Power 2 (P2) = 96W.

Power 3 (P3) = 31.2 W.

Total power =..?

Total power = P1 + P2 + P3

Total power = 48 + 96 + 31.2

Total power = 175.2 W

Therefore, the total power is 175.2 W.

7 0

4 years ago