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givi [52]
3 years ago
15

Why do the planets appear in different locations in the night sky while the pattern of stars in a constellation stays the same?

Physics
2 answers:
valentinak56 [21]3 years ago
8 0
Planets are consantly moving and are relitivly nearby so their movment has a big impact on our veiw o them but stars are far away so it take a huge amount of movement to change our view of them
Goshia [24]3 years ago
7 0
I'm sure you've noticed that an airplane high in the sky, far away
from you, looks like it's moving very slowly.  At the same time,
somebody passing you on a skateboard whizzes past you at
high speed.  The farther away something is from you, the slower
it appears to move.

The nearest star outside the solar system is almost 32 thousand times
as far away from us as the farthest visible planet (Saturn) is, and all of the
other stars are farther than that. 

That's why you have to wait a few thousand years before you notice
that the shape of a constellation has changed.

To put it a slightly different way . . . Everything is in motion.  The motion is
more noticeable for nearby things, and less noticeable for farther-away things. 
Objects within our solar system are the only ones near enough so that a human
lifetime is a long enough period in which to notice the change in their position.
Even Pluto moves less then 1.5° against the 'background' stars in a whole year.

This all makes me feel small.  How about you ?
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leva [86]
In a parallel connection, the equivalent resistance is the summation of the inverse of each individual resistances. It is mathematically expressed as 1/ Req = 1/10 +1/20 + 1/25 = 5.263 ohms. Also, the voltage across each resistor is equal to the input voltage, therefore I = 100 / 10 = 10 Amps. I hope this helped you.
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What is night vision pls tell fast
mario62 [17]

Answer:

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Explanation:

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3 years ago
Can we take water instead of clock oil in Milikan oil drop experiment. Explain.​
ololo11 [35]

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7 0
2 years ago
Two blocks are connected by a massless cable which goes through the center of a rotating turntable. The blocks have masses M1 =
Airida [17]

Answer:

If the final question is; at what velocity will the first block start to move outward in m/s?

v = 3.5596 \frac{m}{s}

Explanation:

The motion have the velocity that will make the block move using:

F_{1}*F_{r}+ F_{2}= Ec \\Ec= \frac{M*v^{2} }{r}

m_{1} = 1.2 Kg

m_{2} = 2.8 Kg

r = 0,45 m

μs= 0,54

Resolving:

\frac{m_{1}*v^{2}  }{r} = us*m_{1}* g + m_{2} * g

v^{2} = \frac{((us *m_{1} + m_{2})*g )* r}{m_{1} }

v^{2} = \frac{((0.54 *1.2 + 2.8)*9.8 )* 0.45}{1.2}

v^{2} = 12.6714 \frac{m^{2} }{s^{2} }

v = 3.559 \frac{m}{s}

4 0
3 years ago
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