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Maru [420]
3 years ago
8

Using a rope that will snap if the tension in it exceeds 379 N, you need to lower a bundle of old roofing material weighing 473

N from a point 6.50 m above the ground. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping
Physics
1 answer:
Tema [17]3 years ago
8 0

Answer:

Acceleration = a = -1.94 m/s^2

Explanation:

Weight of the bundle = W = mg  

                      m = W/g = 473/9.8  

                      m = 48.26 kg

There are two forces acting on the bundle such as tension in the upward direction and weight in the downward direction. So, according to newton’s second law of motion:  

Sum of forces = ma  

                           T - W = ma  

                           a = (T – W)/m

                           a = (379 - 473)/48.26

                           a = -1.94 m/s^2

Negative sign shows that the acceleration is in the downward direction.

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Nataly [62]

Answer:v_1=28.4 cm/s

Explanation:

Given

mass of marble m_1=27 gm

velocity of marble u_1=56.8 cm/s \approx 0.568 m/s

mass of second marble m_2=13.5 gm

Velocity of second marble u_2=14.2 cm/s \approx 0.142 m/s

After collision 13.5 gm marble moves to the right  at i.e. v_2=71 cm/s

Conserving momentum

m_1u_1+m_2u_2=m_1v_1+m_2v_2

27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71

1533.6+191.7=27\cdot v_1+958.5

27\cdot v_1=766.8

v_1=\frac{766.8}{27}=28.4 cm/s

7 0
3 years ago
Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?
vfiekz [6]

Explanation:

London dispersion forces will form between non-polar molecules(polar ) that are symmetrical  like O₂, H₂, Cl₂ and noble gases.

  • The attraction here is because non-polar molecules becomes polar due to the constant motion of its electrons.
  • This lead to an uneven charge distribution at an instant.
  • A temporary  dipole or instantaneous dipole forms.
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Learn more:

Intermolecular forces brainly.com/question/10602513

#learnwithBrainly

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3 years ago
We know velocity of sound v=a₩(omega), but speed does not depend on amplitude, why?
MrRissso [65]
Hope it helps............

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When a driver presses the brake pedal, his car can stop with an acceleration of -5.4m/s^2. How far will the car travel while com
Dahasolnce [82]
Information that is given:
a = -5.4m/s^2
v0 = 25 m/s
---------------------
S = ?
Calculate the S(distance car traveled) with the formula for velocity of decelerated motion:
v^2 = v0^2 - 2aS
The velocity at the end of the motion equals zero (0) because the car stops, so v=0.
0 = v0^2 - 2aS
v0^2 = 2aS
S = v0^2/2a
S = (25 m/s)^2/(2×5.4 m/s^2)
S = (25 m/s)^2/(10.8 m/s^2)
S = (625 m^2/s^2)/(10.8 m/s^2)
S = 57.87 m
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earnstyle [38]
The answer to the question is True
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