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Maru [420]
3 years ago
8

Using a rope that will snap if the tension in it exceeds 379 N, you need to lower a bundle of old roofing material weighing 473

N from a point 6.50 m above the ground. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping
Physics
1 answer:
Tema [17]3 years ago
8 0

Answer:

Acceleration = a = -1.94 m/s^2

Explanation:

Weight of the bundle = W = mg  

                      m = W/g = 473/9.8  

                      m = 48.26 kg

There are two forces acting on the bundle such as tension in the upward direction and weight in the downward direction. So, according to newton’s second law of motion:  

Sum of forces = ma  

                           T - W = ma  

                           a = (T – W)/m

                           a = (379 - 473)/48.26

                           a = -1.94 m/s^2

Negative sign shows that the acceleration is in the downward direction.

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The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a
s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = 0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg

r = Radius of orbit of planet = 0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m

v = Orbital speed

The kinetic and potential energy balance is given by

\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days  

The orbital period is 14.45 days

5 0
3 years ago
The length of a wire 2.00 m is measured as 2.02m. What is the percentage error in the measurement?
n200080 [17]

Answer:

1%

Explanation:

Percent error can be found by dividing the absolute error (difference between measure and actual value) by the actual value, then multiplying by 100.

Percent Error=\frac{V_{measured}- V_{true} } {V_{true}} *100

The measured value is 2.02 meters and the actual value is 2.00 meters.

V_{measured}=2.02\\\\V_{true}=2.00

Percent Error=\frac{2.02-2.00}{2.00} *100

First, evaluate the fraction. Subtract 2.00 from 2.02

Percent Error=\frac{0.02}{2.00}*100

Next, divide 0.02 by 2.00

PercentError=0.01 *100

Finally, multiply 0.01 and 100.

Percent  Error=1\\Percent  Error= 1 \%

The percent error is 1%.

6 0
3 years ago
Which of the following statements best describes the method of energy conservation known as cogeneration?
Mazyrski [523]

Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

6 0
2 years ago
A house that was heated by electric resistance heaters consumed 1200 kWh of electric energy in a winter month. If this house wer
Marysya12 [62]

Answer:

$84

Explanation:

The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.

The heater consumed by the heater is 1200 kWh.

For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:

Electric input to heat pump = 1200 / 2.4 = 500 kWh

That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh

The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh

Money saved = $0.12/kWh * 700 kWh = $84

6 0
3 years ago
Mass can be expressed in
stich3 [128]

Answer:

mass can be expressed in newtons

3 0
2 years ago
Read 2 more answers
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