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Maru [420]
3 years ago
8

Using a rope that will snap if the tension in it exceeds 379 N, you need to lower a bundle of old roofing material weighing 473

N from a point 6.50 m above the ground. (a) What magnitude of the bundle's acceleration will put the rope on the verge of snapping
Physics
1 answer:
Tema [17]3 years ago
8 0

Answer:

Acceleration = a = -1.94 m/s^2

Explanation:

Weight of the bundle = W = mg  

                      m = W/g = 473/9.8  

                      m = 48.26 kg

There are two forces acting on the bundle such as tension in the upward direction and weight in the downward direction. So, according to newton’s second law of motion:  

Sum of forces = ma  

                           T - W = ma  

                           a = (T – W)/m

                           a = (379 - 473)/48.26

                           a = -1.94 m/s^2

Negative sign shows that the acceleration is in the downward direction.

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What is the motional kinetic energy of a 25 kg object moving at a speed of 10 m/s?
Soloha48 [4]

1250kgm²/s is the motional kinetic energy of a 25kg object moving at a speed of 10m/s

Kinetic energy of an object is defined as the energy which is possessed when that is  in motion. It is the energy of the kinetic mass of an object. Kinetic energy is never negative and is a scalar quantity. That is, it shows only size, not orientation.

Given to us

Mass of the object, m=25kg

Velocity of the object, v=10m/s  

K.E=1/2x25x10²

 =1250

Kinetic energy is directly proportional to the mass and velocity squared (K.E.) of an object. =1/2xMxV². If the mass is in kilograms and the velocity is in meters/second, then the kinetic energy is in kilograms - meters squared/second.

Learn ore about Kinetic energy here brainly.com/question/25959744

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5 0
1 year ago
Is it true or false
tester [92]

Answer:

false

Explanation:

8 0
2 years ago
A car traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. What was its acceleration? Round your answe
Contact [7]

Answer:

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2

Acceleration is 51.94 ft/s²

v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s

Final velocity at this time is 257.63 ft/s

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It would tack about 3.2 h

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When the area of block increases for constant force, the
Lemur [1.5K]

Answer: B

adding force will add accesion

7 0
3 years ago
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