All categories

3 years ago

5. Find the measure of x and and the angle measure. (3x - 15) (2x + 7)

Mathematics

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

here's the answer to your question

You might be interested in

Melissa is standing 40 ft from a tree. The angle of elevation from where she is standing on the ground to the top of the tree is

bagirrra123 [75]

Tan(angle) = opposite length/ adjacent length

Tan(50) = h/40
h = 40 x tan(50)
h = 47.67 or 47.7 feet

3 0

3 years ago

Read 2 more answers

If the time period of a vibrating body is 0.4 s, then it’s frequency is

irina1246 [14]

Answer:

2.5

Step-by-step explanation:

6 0

3 years ago

If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n

pashok25 [27]

Answer:

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the $\sum^\infty_{n=0}C_n8^n$ is convergent

Therefore,

(a) $\sum^\infty_{n=0}C_n(-3)^n$ The power series $\sum C_nx^n$ has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴ $\sum^\infty_{n=0}C_n(-3)^n$ is convergent.

(b) $\sum^\infty_{n=0}C_n(-8)^n$ -8 could be right on the edge of the interval of convergence, and so might not converge

8 0

3 years ago

In X = 4 Answer options; A: x=e^4 B: x=(4/e) C: x=4e D: x=4^e

marshall27 [118]

Answer:

the answer is x=e⁴........

7 0

3 years ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago