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Zepler [3.9K]
4 years ago
8

002 10.0 points

Chemistry
1 answer:
likoan [24]4 years ago
5 0

Answer:

option 3 = 3.41 m

Explanation:

Given data:

Frequency of signals = 88.1 MHz or 88.1 × 10⁶ Hz

Wavelength = ?

Solution:

Formula:

λ = c / f

λ = Wavelength

c = speed of light

f = frequency

λ = c / f

λ = 3 × 10⁸ m.s⁻¹ /  88.1 × 10⁶ s⁻¹

λ = 0.0341 × 10² m or 3.41 m

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An important reaction sequence in the industrial production of nitric acid is the following:
Nataly_w [17]

Answer:

25.0 mol O₂ are required in the second reaction

Explanation:

N₂ (g) + 3H₂ (g)  →  2NH₃ (g)

4NH₃ (g)  +  5O₂ (g)  →  4NO (g) + 6 H₂O(l)

Molar ratio in first reaction is 1:2

For every mol of N₂. I make 2 moles of ammonia. If I have 20 moles of N₂, i'm going to get, 40 moles of ammonia.

In the second reaction, molar ratio between products is 4:5.

If I obtained 40 moles of ammonia in first step, let's prepare the rule of three.

4 moles of ammonia react with 5 moles of O₂

40 moles of ammonia react with ( 40.5) /4 = 25moles

5 0
4 years ago
Does sound have color? why do you have this opinion (base your answer on wavelengths)
mash [69]

Answer:

Yep. Many of the sounds we associate with white noise are actually pink noise, or brown, or green, or blue. In audio engineering, there's a whole rainbow of noise colors, each with its own unique properties, that are used to produce music, help relaxation, and describe natural rhythms like the human heartbeat.

Explanation:

8 0
3 years ago
6) What types of atomic orbitals are in the third principal energy
Bumek [7]

Answer:

Types of atomic orbitals present in the third principal energy are <u>s, p and d only .</u>

Explanation:

  • <u>OPTION A-:  s and p atomic orbitals -</u> these two orbitals are present in second principal energy level. Therefore , the option is incorrect.
  • <u> OPTION B-: p and d only -</u> This option is wrong as there is no such principal level energy where , s atomic orbital is absent .

  • <u>OPTION C-: s , p and d only -</u>these orbitals are present in<u> third principal energy level</u>. The third major level of energy has one orbital, three orbitals of p, and five orbitals of d, each of which can contain up to 10 electrons. The third stage thus holds a maximum of 18 electrons. This option is correct .
  • <u>OPTION D-: s , p, d and f only -</u>There is also a f sublevel at the <u>fourth and higher stages,</u> containing seven f orbitals, which can accommodate up to 14 electrons at most. Therefore, up to 32 electrons will hold the fourth level: 2 in the s orbital, 6 in the three p orbitals, 10 in the five d orbitals, and 14 in the seven f orbitals. This option is incorrect .

<u>Thus , the correct option is C (s , p and d only .)</u>

6 0
4 years ago
What is gonna be the density of a block charger that is 22g and 210 cm3
Taya2010 [7]

Answer:

Control group

7 0
4 years ago
Helium is located in group 8A but does not have eight valence electrons. Why is it located in 8A, not 2A?
astraxan [27]

Answer:

its outermost shell is completely full making it extremely stable.

Explanation:

It only has two electrons in its outer shell so its valence electron configuration is 1s2. Even though it only has two electrons, it is grouped with elements that have eight valence electrons. Helium is still happy because its outermost shell is completely full making it extremely stable.

5 0
3 years ago
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