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Vikentia [17]
3 years ago
6

Consider the reaction, C2H4(g) + H2(g) - C2H6(8), where AH = -137 kJ. How many kilojoules are released when 3.5 mol of CH4

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer: 480 kJ of energy is released when 3.5 mol of C_2H_4 reacts.

Explanation:

The balanced chemical reaction is:

C_2H_4(g)+H_2(g)\rightarrow C_2H_6(g)  \Delta H=-137kJ

Thus it is given that the reaction is exothermic (heat energy is released) as enthalpy change for the reaction is negative.

1 mole of C_2H_4 on reacting gives = 137 kJ of energy

Thus 3.5 moles  of C_2H_4 on reacting gives = \frac{137}{1}\times 3.5=480 kJ of energy

Thus 480 kJ of energy is released when 3.5 mol of C_2H_4 reacts.

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DNA molecules are replicated during what part of the cell cycle
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8 0
3 years ago
Use the van der Waals equation and the ideal gas equation to calculate the volume of 1.000 mol of neon at a pressure of 500.0 at
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Use the van der Waals equation and the ideal gas equation to calculate the volume of 1.000 mol of neon at a pressure of 500.0 atm and a temperature of 355.0 K.

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4 0
2 years ago
Competition is one of the causes of evolution we have discussed before, but it is an example of what type of factor?
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Biotic factor

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5 0
3 years ago
A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M
igor_vitrenko [27]

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

M_1V_1=M_2V_2

where,

M_1 = molarity of aqueous sodium carbonate

M_2 = molarity of aqueous sodium carbonate stock solution

V_1 = volume of aqueous sodium carbonate

V_2 = volume of aqueous sodium carbonate stock solution

Given:

M_1 = 1.00 M

M_2 = 1.58 M

V_1 = 575 mL

V_2 = ?

Now put all the given values in the above formula, we get:

1.00M\times 575mL=1.58M\times V_2

V_2=363.92mL\approx 364mL

Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.

8 0
3 years ago
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