To determine the amplitude of a wave, you would need to know the : B. Maximum displacement of the wave from the equilibrium position
You can find out the displacement by counting the waves that is
written on the Graph
Hope this helps
Answer:
S=
2
1
gt
2
........(1)
And that of the other stone is
S=u(t−n)+
2
1
[g(t−n)
2
]........(2)
Since both the stones meet at the distance so equation (1)and equation(2) will be equal
2
1
gt
2
=u(t−n)+
2
1
[g(t−n)
2
]
gt
2
=2ut−2un+gt
2
+gn
2
−2gnt
t(2gn−2u)=gn
2
−2un
t=
(gn−u)
n(
2
gn
−u)
now putting value of t in equation(1)
s=
2
g
⎣
⎢
⎡
gn−u
2
[n(
2
gn
−u)]
⎦
⎥
⎤
2
S=
2
g
⎣
⎢
⎡
(gn−u)
2
n(
2
gn
−u)
⎦
⎥
⎤
Explanation:
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Given:
w = z(t)= γ − β*t^2
Differentiating both sides with respect to t, we get:
α = z(t) = -2βt
Given: <span> γ = 5.35 rad/s and β = 0.810 rad/s3
</span>
so, For t = 3 sec,
angular acceleration = -2 * 0.810 * 3 = <span>-4.86</span>
