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Aleksandr-060686 [28]
3 years ago
7

What are in the energy levels that surround the nucleus of an atom?

Chemistry
1 answer:
sasho [114]3 years ago
4 0
Electrons are the thing in the outer energy levels
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Balance this equation please.
forsale [732]
2K + 2H2O = 2KOH + H2
6 0
3 years ago
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What is particles in chemistry?
castortr0y [4]
A particle<span> is a minute fragment or quantity of matter. In the physical sciences, a </span>particle<span> is a small localized object to which can be ascribed several physical or a</span> chemical<span> properties such as volume or mass.</span>
4 0
3 years ago
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
Astronomers often scan the sky using devices called radio
sukhopar [10]

Answer:

A radio telescope is simply a telescope that is designed to receive radio waves from space.

radio telescopes helps to study naturally occurring radio light from stars, galaxies, black holes, and other astronomical objects. We can also use them to transmit and reflect radio light off of planetary bodies in our solar system.

6 0
2 years ago
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3. How many grams of water will be produced from 15.0 grams of Methane? *<br> CH4 +2 02 → CO2 + 2H2O
jok3333 [9.3K]
CH4 + 2O2 = CO2 + 2H2O

According to molar weights :

16 gm CH4 + 64 gm O2 = 44 gm CO2 + 36 gm H2O

Since 16 gm CH4 produce 36 gm H2O

Hence 2.5 gmCH4 produce 36×2.5/16 gm H2O

= 5.265 gm of H2O
2.1K viewsView 2 Upvoters

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