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1 year ago

Which of the following types of radiation can be blocked with only a sheet of paper?

Chemistry

2 answers:

barxatty [35]1 year ago

7 0

Hello there!

Alpha decay can be blocked with only a sheet of paper.
Gamma rays can only be blocked with something thick and dense.
Beta rays can be blocked with something less dense, but thicker than paper.

Hope this helps. Let me know if you have any questions.

~GracefulGirlie :)

Good luck on your assignment.

garri49 [273]1 year ago

5 0

Answer:

Alpha decay

Explanation:

Alpha decay can be blocked with only a sheet of paper.

Extra info : -

In general, alpha particles have a very limited ability to penetrate other materials. In other words, these particles of ionizing radiation can be blocked by a sheet of paper, skin, or even a few inches of air.

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Murrr4er [49]

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2 years ago

how much energy has your body used, in joules, if your health device indicates that 450 calories were burned during your workout

Likurg_2 [28]

Answer:

Total energy consumed = 1,882.8 joules

Explanation:

Given:

Calories burned = 450 calories

Find:

Total energy consumed

Computation:

1 calorie = 4.184 joules

So,

450 calories = 4.184 × 450

450 calories = 1,882.8 joules

Total energy consumed = 1,882.8 joules

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2 years ago

What is the oxidation number of chromium in dichromate ion, cr2o72-?

castortr0y [4]

Oxidation number is charge of element in compound. Can be neutral, positive or negative.
Oxygen in dichromate has oxidation number -2, becauce there are seven oxygens, net oxidation number of oxygen is -14.
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x= +6, oxidation number of one chromium is +6.

8 0

3 years ago

What do you think will happen to the Kool-Aid drink after it is boiled? CER(Claim,CITE evidence and reasoning) response THANK U

mafiozo [28]

Answer:

It is just sugar decomposing to a dark tar looking goo.

Explanation:

Cite: What happens after you boil kool-aid

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2 years ago

Write the two balanced equations, one for the incomplete combustion of methane (to form carbon monoxide and water vapor), and an

kompoz [17]

Answer:

$2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\$

Explanation:

$2CH_{4(g)} +3O_{2(g)} -->2CO(g)+4H_{2}O_{(g)}\\CH_{4(g)} +2O_{2(g)} -->CO_{2(g)} +2H_{2}O_{(g)} \\$

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2 years ago