1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KengaRu [80]
2 years ago
12

Which of the following types of radiation can be blocked with only a sheet of paper?

Chemistry
2 answers:
barxatty [35]2 years ago
7 0

Hello there!

  • Alpha decay can be blocked with only a sheet of paper.
  • Gamma rays can only be blocked with something thick and dense.
  • Beta rays can be blocked with something less dense, but thicker than paper.

Hope this helps. Let me know if you have any questions.

~GracefulGirlie :)

Good luck on your assignment.

garri49 [273]2 years ago
5 0

Answer:

Alpha decay

Explanation:

Alpha decay can be blocked with only a sheet of paper.

Extra info : -

In general, alpha particles have a very limited ability to penetrate other materials. In other words, these particles of ionizing radiation can be blocked by a sheet of paper, skin, or even a few inches of air.

You might be interested in
Darwin observed how farmers and breeders produced many kinds of farm animals and plants. These plants and animals had traits tha
NISA [10]

the answer is A......

it is supported by practical evidence and examples. this is the answer because he tried and tested many different ways to see what would happen so he is happy with the conclusion that what he tested is what he gets.

3 0
3 years ago
Read 2 more answers
Which of the following substances is classified as a solution?
Ainat [17]

Answer:

Salt water

Explanation:

Please mark me brainliest and thank me.

3 0
3 years ago
Read 2 more answers
Which of the following atoms would have the greatest velocity of each atom had the same kinetic energy?
storchak [24]
The answer would be C oxygen
3 0
3 years ago
Read 2 more answers
Please help me with this science question
nalin [4]

Answer:

B

Explanation:

4 0
3 years ago
Suppose a system returns to its original overall, internal energy ((∆U) after the following changes. In step 1, 25 J of work is
Brums [2.3K]

Answer:

Heat transfer in step 2 = 47.75 J

Explanation:

Internal energy = heat + work done

U = Q + W

In a cyclic process the total internal energy change of the system = 0.

In the process there are two steps. The total heat exchange in the process is the sum of heat exchanges in the two processes.

We have to find the heat exchange in step 2.

In step 1,

W = 1.25 J          Q = -37 J

U_{1} = -37 + 1.25 = -35.75 J

In step 2, the internal energy change will be negative of that in step 1.

U = 35.75 J

W = -12 J

U = Q + W

35.75 = Q -12

Q = 47.75 J

Heat transfer in step 2 = 47.75 J

6 0
3 years ago
Other questions:
  • At 25 ∘C , the equilibrium partial pressures for the reaction were found to be PA=5.16 bar, PB=5.04 bar, PC=4.11 bar, and PD=4.8
    11·1 answer
  • What is the independent variable for a dry ice experiment
    12·2 answers
  • An ice cube is dropped into boiling water. How will heat flow between the water and the ice cube?
    11·2 answers
  • Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro
    9·1 answer
  • If the flour mixture is then taken and put into the oven for about 20 minutes, it turns into something very tasty. What kind of
    6·1 answer
  • How can we tell macronutrients apart?
    9·1 answer
  • What do you understand by a chemical reaction
    15·1 answer
  • Which list contains only animal phyla? mosses, annelids, conifers, chordates mosses, ferns, conifers, flowering plants cnidarian
    7·2 answers
  • Calculate the number of moles in 4.22x1022 molecules of H,O
    14·1 answer
  • Challenge Air is a mixture of gases. By percentage, it is roughly 78 percent nitrogen, 21 percent oxygen, and 1 percent argon. (
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!