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2 years ago

The smallest ionic radius among the following. Li Mg Na+ be+

1 answer:

5 0

The correct answer is Be+

That is because it lost a single electron but still has the same number of protons, and thus the effective charge attracting each electron is greater, which in turn makes the radius even smaller

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A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio

-Dominant- [34]

Answer:

The concentration of new solution will be 1×10∧-7 M.

Solution:

Data Given

given mass of fluoxymesterone =16.8mg = 0.0168 g

molar mass of fluoxymesterone = 336g/mol

vol. of fluoxymesterone = 500.0 ml = 0.500 L

Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

Stock Solution : New Solution

M1.V1 = M2.V2

( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

1 × 10∧-7 = M2

Result:

The concentration of new solution M2 will be 1 × 10∧-7

3 0

3 years ago

-- A scientist combines 14 grams of potassium nitrate with an unknown amount of

igor_vitrenko [27]

Answer:

The unknown amount of potassium chloride is 13.6 grams.

Explanation:

The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.

The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:

$m_{r} = m_{p}$

Where r is for reactants and p is for products

$m_{KNO_{3}} + m_{KCl} = m_{p}$

$14 g + m_{KCl} = 27.6 g$

$m_{KCl} = 27.6 g - 14 g = 13.6 g$

Therefore, the unknown amount of potassium chloride is 13.6 grams.

I hope it helps you!

5 0

3 years ago

Consider the following reaction and situations 1 through 10. In the spaces provided, clearly indicate the best response to each

olchik [2.2K]

Answer:

1. C. no change

2. A. increase

3. E. shift to the right

4. A. increase

5. E. shift to the right

6. A. increase

7. F. cannot be determined

8. B increase

9. D. shift to the left

10 F. cannot be determined

Explanation:

According to Le Chaterlier principle, when a reaction is in equilibrium and one of the constraints that affect reactions is applied, the equilibrium will shift so as annul the effects of the constraints.

From the equation: C(s) + H2O(g) ⇌ CO(g) + H2(g),

H is greater than 0, meaning that the system is endothermic, that is energy is absorbed.

1. If the pressure of the system is increased, there would be no change to the system because there are equal number of moles of products and reactants.

2. If H2 concentration is decreased, the equilibrium will shift to the right and more products will be formed. Hence, the concentration of CO will increase.

3. If H2 concentration is decreased, the equilibrium will shift to the right to annul the effects of the decrease in the concentration of a product.

4. If the concentration of H2 is increased, the equilibrium will shift to the left to annul the effects of increased concentration of a product. Hence, more H2O would be formed.

5. If H2 (a product) is removed, and C (a reactant) is added, more of the products will be formed in order to annul the effects of the actions. Hence, equilibrium will shift to the right.

6. If the amount of C (a reactant) is increased, the equilibrium will shift to the right. Hence, more H2 will be formed.

7. The reaction is endothermic, hence an increase in temperature will ordinarily shift the equilibrium to the right. However, the addition of H2 (a product) is supposed to shift the equilibrium to the left. Hence, the effects of simultaneous addition of the two actions become indeterminate.

8. Since the reaction is endothermic, increase in the temperature of the system will shift the equilibrium to the right. Hence, more CO will be formed.

9. If the concentration of H2O (a reactant) is decreased and that of CO (a product) is increased, both actions lead to the equilibrium being shifted to the left.

10. Addition of catalyst to the system will only speed up the rate at which the system reach the equilibrium.

5 0

2 years ago

How many grams is 3.35 moles of hcl

lions [1.4K]

Do this

3.35mol HCl | 34.46g HCl
------------------------------------
1 | 1mol HCl
Multiply all the numbers on top by all the numbers on bottom.

7 0

3 years ago

A piston in a heat engine does 500 joules of work, and 1400 joules of heat are added to the system. Determine the change in inte

san4es73 [151]

Answer : The change in internal energy is, 900 Joules.

Solution : Given,

Heat given to the system = +1400 J

Work done by the system = -500 J

Change in internal energy is equal to the sum of heat energy and work done.

Formula used :

$\Delta U=q+w$

where,

$\Delta U$ = change in internal energy

q = heat energy

w = work done

As per question, heat is added to the system that means, q is positive and work done by the system that means, w is negative.

Now put all the given values in the above formula, we get

$\Delta U=(+1400J)+(-500J)=900J$

Therefore, the change in internal energy is 900 J.

The change in internal energy depends on the heat energy and work done. As we will change in the heat energy and work done, then changes will occur in the internal energy. Hence, the energy is conserved.

8 0

2 years ago