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alex41 [277]
3 years ago
7

What is the relationship between stream and drainage basin

Physics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0
Each stream in a drainage system drains into a certain area. In a drainage basin the water falling in the basin drain will fall into the same stream. A drainage divides drawing basin from other drainage basins
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Which of the following is not an example of energy transfer?
Alex787 [66]

Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

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Calculate the force of earth's gravity on a 1kg mass at earth's surface. the mass of the earth is 6.0
jonny [76]

Force of earth gravity on 1 kg mass is 9.8 N.

Since the mass is at earth surface, therefore its distance from the centre of earth is equal to the radius of the earth i.e. 6400 km.

The force of earth gravity is calculated as

F=GMm/r^2 =(6.67*〖10〗^(-11)*6*〖10〗^24*1)/〖(64*〖10〗^6)〗^2 =9.8 N

4 0
3 years ago
If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the accel
Studentka2010 [4]

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

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You push downward on a trunk at an angle 25° below the horizontal with a force of If the trunk is on a flat surface and the coef
Sophie [7]

Complete question is;

You push downward on a trunk at an angle 25° below the horizontal with a force of 750N. if the trunk is on a flat surface and the coefficient of static friction between the surface and the trunk is 0.61, what is the most massive trunk you will be able to move?

Answer:

The most massive trunk is about 81.3 kg

Explanation:

I've attached a free body diagram that depicts this question.

Where;

N = normal force on the trunk

m = mass of the trunk

W = weight of the trunk = mg

F = static frictional force

Using equilibrium of force in vertical direction, we obtain;

N = W + 750 Sin25

N = mg + 750 Sin25    - - - - (eq 1)

Now, we are given that Coefficient of static friction: μ = 0.61

static frictional force is given by the formula;

F = μN

Since N = mg + 750 Sin25, we now have;

F = (0.61) (mg + 750 Sin25)   - - - (eq 2)

Along the horizontal direction, for the trunk to move, force equation must be;

F = 750 Cos25

Thus, we now have;

750 Cos25 = 0.61(mg + 750 Sin25)

g = 9.81.

So,we now have ;

750 Cos25 = 0.61(m(9.81) + 750Sin25)

750 × 0.9063 = 0.61(9.81m + (750 × 0.4226))

Divide both sides by 0.61;

(750 × 0.9063)/0.61 = 9.81m + 316.95

1114.3 = 9.81m + 316.95

1114.3 - 316.95 = 9.81m

797.35 = 9.81m

m = 797.35/9.81

m = 81.3 kg

7 0
3 years ago
Given a sphere with radius r, find the height of a pyramid of minimum volume whose base is a square and whose base and triangula
BaLLatris [955]

Answer:

The Height of a pyramid is 4r.

Explanation:

Explanation is in the following attachments

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