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Akimi4 [234]
3 years ago
5

100 cars on one lane road. When a faster car meets slower car, it travels at slower car's rate.

Physics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer

When 100 cars are on one lane and the faster car of the lane meets the slower car then the rate of the movement of the vehicle is decided by the slowest moving car.

The flow rate of traffic is the rate of the vehicle car a point in the given interval of time.

When the car is moving slowly fast-moving cars will not get the chance to move and they have to follow the slow-moving car.

Hence, it is rightly stated the flow of traffic is decided by slow-moving vehicles.

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Pushing a door closed is an example of force. true or false​
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True

Explanation:

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The plane of a rectangular coil, 7.2 cm by 3.7 cm, is perpendicular to the direction of a uniform magnetic field B. If the coil
netineya [11]

Answer:

The rate of change of magnetic field is 2.23 T/s.              

Explanation:

Given that,

Dimension of rectangular coil is 7.2 cm by 3.7 cm.

Number of turns in the coil, N = 104

Resistance of the coil, R = 12.4 ohms

Current, I = 0.05 A

We need to find the rate of change of magnetic field in the coil. The induced emf is given by the rate of change of magnetic flux. So,

\epsilon=-\dfrac{d\phi}{dt}

Ohm's law is :

\epsilon=IR

So,

IR=-\dfrac{d\phi}{dt}\\\\IR=-\dfrac{d(NBA)}{dt}\\\\IR=-NA\dfrac{dB}{dt}\\\\\dfrac{dB}{dt}=\dfrac{IR}{NA}\\\\\dfrac{dB}{dt}=\dfrac{0.05\times 12.4}{104\times 7.2\times 10^{-2}\times 3.7\times 10^{-2}}\\\\\dfrac{dB}{dt}=2.23\ T/s

So, the rate of change of magnetic field is 2.23 T/s.

4 0
3 years ago
Find the radius Rrigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×
Zinaida [17]

Answer:

r = 1.61 x 10^{11} m

Explanation:

energy radiated (H) = 2.7 x 10^31 W

surface temperature (T)  = 11,000 k

assuming ε = 1 and taking σ = 5.67 x 10^{-8} W/m^{2}.K^{4}

we can find the radius of the star from the equation below

H = A x  ε x σ x T^{4}              

where area (A) = 4 x π x r^{2} (assuming it is a sphere)

therefore  the equation becomes

H = 4 x π x r^{2} x  ε x σ x T^{4}  

2.7 x 10^31  = 4 x π x r^{2} x  1 x 5.67 x 10^{-8}  x (11,000)^{4}

r = \sqrt{\frac{2.7 x 10^31}{4 x π x 1 x 5.67 x 10^{-8}  x (11,000)^{4}} }

r = 1.61 x 10^{11} m

       

4 0
3 years ago
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