Answer:
a) ![\frac{Ws}{Es} = \frac{200}{1+1.2s}](https://tex.z-dn.net/?f=%5Cfrac%7BWs%7D%7BEs%7D%20%20%3D%20%5Cfrac%7B200%7D%7B1%2B1.2s%7D)
b) attached below
c) type zero system
d) k > ![\frac{g}{200}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7B200%7D)
e) The gain K increases above % error as the steady state speed increases
Explanation:
Given data:
Motor voltage = 12 v
steady state speed = 200 rad/s
time taken to reach 63.2% = 1.2 seconds
<u>a) The transfer function of the motor from voltage to speed</u>
let ;
be the transfer function of a motor
when i/p = 12v then steady state speed ( k1 ) = 200 rad/s , St ( time constant ) = 1.2 sec
hence the transfer function of the motor from voltage to speed
= ![\frac{Ws}{Es} = \frac{200}{1+1.2s}](https://tex.z-dn.net/?f=%5Cfrac%7BWs%7D%7BEs%7D%20%20%3D%20%5Cfrac%7B200%7D%7B1%2B1.2s%7D)
<u>b) draw the block diagram of the system with plant controller and the feedback path </u>
attached below is the remaining part of the detailed solution
c) The system is a type-zero system because the pole at the origin is zero
d) ) k > ![\frac{g}{200}](https://tex.z-dn.net/?f=%5Cfrac%7Bg%7D%7B200%7D)