Answer:
The distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2
Explanation:
From the image uploaded, a Face centered cubic structure (100) plane, there is one atom at each of the four cube corners, each of which is shared with four adjacent unit cells, while the center atom lies entirely within the unit cell.
In terms of the atomic radius, R, we determine the distance between the centers of adjacent atoms.
Let this distance = AC
the two adjacent sides = AB and BC
AB = a = 2R
BC = a = 2R
Using Pythagoras theorem
AC² = AB² + BC²
AC² = a² + a²
AC² = 2a²
AC = √2a²
AC = a√2
But a = 2R
AC = 2R√2
Therefore, the distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2
Answer:
COP = 0.090
Explanation:
The general formula for COP is:
COP = Desired Output/Required Input
Here,
Desired Output = Heat removed from water while cooling
Desired Output = (Specific Heat of Water)(Mass of Water)(Change in Temperature)/Time
Desired Output = [(4180 J/kg.k)(3.1 kg)(25 - 11)k]/[(12 hr)(3600 sec/hr)]
Desired Output = 4.199 W
And the required input can be given as electrical power:
Required Input = Electrical Power = (Current)(Voltage)
Required Input = (2.9 A)(16 V) = 46.4 W
Therefore:
COP = 4.199 W/46.4 W
<u>COP = 0.090</u>