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2 answers:

FinnZ [79.3K]3 years ago

7 0

It would be either b or d, but most likely d

Gwar [14]3 years ago

5 0

I would think d because b and c aren’t correct

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I need help with this

fredd [130]

We have here what is known as parallel combination of resistors.

Using the relation:

$\frac{1}{ r_{eff} } = \frac{1}{ r_{1} } + \frac{1}{ r_{2} } + \frac{1}{ r_{3} }.. . + \frac{1}{ r_{n} } \\$
And then we can turn take the inverse to get the effective resistance.

Where r is the magnitude of the resistance offered by each resistor.

In this case we have,
(every term has an mho in the end)
$\frac{1}{10000} + \frac{1}{2000} + \frac{1}{1000} \\ \\ = \frac{1}{1000} ( \frac{1}{10} + \frac{1}{2} + \frac{1}{1} ) \\ \\ = \frac{1}{1000} ( \frac{31}{20}) \\ \\ = \frac{31}{20000}$

To ger effective resistance take the inverse:
we get,
$\frac{20000}{31} \: ohm \\ = 645 .16 \: ohm$

The potential difference is of 9V.

So the current flowing using ohm's law,

V = IR

will be, 0.0139 Amperes.

7 0

3 years ago

A 5.00 g projectile has a velocity of 255 m/s right. Find the force to stop this projectile in 1.45s.

Stells [14]

Explanation:

The X-component of the velocity = Vcosx. Where, V = magnitude of the velocity. The x component of velocity will depend on the diagram. It the angle is measured from the x-axis which is considered the horizontal then Vx = Vcos(theta). The magnitudes of the components of velocity v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12. Derivation of the Trajectory Formula.

y = refers to the vertical position of the object in meters. x = refers to the horizontal position of the object in meters. Horizontal velocity component: Vx = V * cos(α)

Vertical velocity component: Vy = V * sin(α)

Time of flight: t = [Vy + √(Vy² + 2 * g * h)] / g.

Range of the projectile: R = Vx * [Vy + √(Vy² + 2 * g * h)] / g.

Maximum height: hmax = h + Vy² / (2 * g)

8 0

3 years ago

kyle is holding a nag of 250 jelly beans. when mark takes out two jellybeans, kyle is not able to tell a difference. this illust

andreev551 [17]

This illustrates Kyle's inability to accurately sense the weight of the nag.

7 0

3 years ago

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