1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bekas [8.4K]
3 years ago
9

A ball of putty is dropped from a height of 2 m onto a hard floor, where it sticks. Part A What object or objects need to be inc

luded within the system if the system is to be isolated during this process?
1) Solar system
2) floor,ball
3) human
4) dropping a ball
5) earth
Physics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

As the ball falls from a certain height and then sticks to the floor so this system will include the following objects.

ball, floor, Earth

2 is a correct option.

You might be interested in
What happens when a roller coaster car moves down from the top of a hill?
VARVARA [1.3K]

-- It accelerates.
-- Its speed increases.
-- It gains momentum.
-- It loses altitude.
-- It loses potential energy.
-- It gains kinetic energy.
-- Its wheels make a lot of noise.
-- Everybody screams.

6 0
3 years ago
Read 2 more answers
Can someone help me due at 1:00 PM plus 100 points <br><br>questions B,C,D
vagabundo [1.1K]
<h3>b. ML </h3><h3>c. M</h3><h3>d. Kg</h3>

<h3>Hope it helps...</h3>
6 0
3 years ago
Read 2 more answers
A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformati
Slav-nsk [51]

The question is incomplete. The complete question is :

A viscoelastic polymer that can be assumed to obey the Boltzmann superposition principle is subjected to the following deformation cycle. At a time, t = 0, a tensile stress of 20 MPa is applied instantaneously and maintained for 100 s. The stress is then removed at a rate of 0.2 MPa s−1 until the polymer is unloaded. If the creep compliance of the material is given by:

J(t) = Jo (1 - exp (-t/to))

Where,

Jo= 3m^2/ GPA

to= 200s

Determine

a) the strain after 100's (before stress is reversed)

b) the residual strain when stress falls to zero.

Answer:

a)-60GPA

b) 0

Explanation:

Given t= 0,

σ = 20Mpa

Change in σ= 0.2Mpas^-1

For creep compliance material,

J(t) = Jo (1 - exp (-t/to))

J(t) = 3 (1 - exp (-0/100))= 3m^2/Gpa

a) t= 100s

E(t)= ΔσJ (t - Jo)

= 0.2 × 3 ( 100 - 200 )

= 0.6 (-100)

= - 60 GPA

Residual strain, σ= 0

E(t)= Jσ (Jo) ∫t (t - Jo) dt

3 × 0 × 200 ∫t (t - Jo) dt

E(t) = 0

5 0
3 years ago
9. Consider the elbow to be flexed at 90 degrees with the forearm parallel to the ground and the upper arm perpendicular to the
mojhsa [17]

Answer:

Moment about SHOULDER  ∑ τ = 3.17 N / m,

Moment respect to ELBOW   Στ= 2.80 N m

Explanation:

For this exercise we can use Newton's second law relationships for rotational motion

         ∑ τ = I α

   

The moment is requested on the elbow and shoulder at the initial instant, just when the movement begins.

They indicate the angular acceleration, for which we must look for the moments of inertia of the elements involved

The mass of the forearm with the included weight is approximately 2.3 kg, with a length of about 50cm

Moment about SHOULDER

          ∑ τ = I α

           I = I_forearm + I_sphere

the forearm can be approximated as a fixed bar at one end

            I_forearm = ⅓ m L²

the moment of inertia of the mass in the hand, let's approach as punctual

            I_mass = m L²

we substitute

           ∑ τ = (⅓ m L² + M L²) α

let's calculate

          ∑ τ = (⅓ 2.3 0.5² + 0.5 0.5²) 10

           ∑ τ = 3.17 N / m

Moment with respect to ELBOW

In this case, the arm exerts an upward force (muscle) that is about 3 cm from the elbow

         Στ = I α

         I = I_ forearm + I_mass

         I = ⅓ m (L-0.03)² + M (L-0.03)²

         

let's calculate

        i = ⅓ 2.3 0.47² + 0.5 0.47²

        I = 0.2798 Kg m²

        Στ = 0.2798 10

        Στ= 2.80 N m

3 0
3 years ago
A mass on a spring with k=88.7 N/m oscillates 15 times in 9.24s. what is the objects mass? unit=kg?
sweet [91]

The mass on the spring is 0.86 kg

Explanation:

The period of a mass-spring system is given by the equation

T=2\pi \sqrt{\frac{m}{k}}

where

m is the mass

k is the spring constant

In this problem, we have:

k = 88.7 N/m is the spring constant

The system makes 15 oscillations in 9.24 s: therefore, the period of the system is

T=\frac{9.24}{15}=0.62 s

Now we can re-arrange the first equation  to solve for the mass:

m=k(\frac{T}{2\pi})^2=(88.7)(\frac{0.62}{2\pi})^2=0.86 kg

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

3 0
3 years ago
Other questions:
  • What is meant by saying that a wave has a low frequency?
    13·2 answers
  • A 12 v automobile battery is connected to an electric starter motor. the current through the motor is 246
    9·1 answer
  • Which hemisphere is experiencing summer in july?
    5·1 answer
  • Assume an 8-kg bowling ball moving at 2m/s bounces off a spring at the same speed that it had before bouncing.What is the moment
    6·1 answer
  • How many ohms of resistance must be present in a circuit that has 120 volts and a current of 10 amps
    15·2 answers
  • An expanding gas does 153 J of work on its surroundings at a constant pressure of 1.01 atm. If the gas initially occupied 68.0 m
    9·1 answer
  • The cheetah is one of the fastest accelerating animals, for it can go from rest to 34.5 m/s in 3.57 s. If its mass is 112 kg, de
    13·1 answer
  • 4. Density is a property of all matter.
    7·1 answer
  • In the compound CaCO3 at the end of the compound represents the number of
    12·1 answer
  • ] After treatment, hospital equipment may become contaminated.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!