2 years ago

What is the resistance of a voltage of 65 V and a current of 2.2 A? Include units.

Physics

1 answer:

kozerog [31]2 years ago

4 0

Answer:

29.5 ohms

Explanation:

R= V/I

= 65 / 2.2

= 29.5 ohms

You might be interested in

A 50.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and the

Dimas [21]

Answer:

98N and 147N

Explanation:

We have the following information:

$m=50kg\\\mu_s =0.4\\\mu_k = 0.2\\F=140N$

We can find the static fricton force as follow,

$F=\mu_s * N$

Where N is the normal force (mg)

$F=0.3*50*9.8\\F=147N$

Static friction force at 147N is greater than the force applied hence body does not move.

$F=\mu_k N = 0.2*50*9.8= 98N$

3 0

3 years ago

If a rock has a weight of 30 N on Earth, would its weight be more or less if it was on Jupiter (gravity on Jupiter = 25 m/s2)?

goldenfox [79]

I’m sorry this is not going as planned

8 0

2 years ago

Show that the units N/kg can be written using only units of meters (m) and second (s). Is this a unit of mass ,acceleration or f

nikdorinn [45]

<span>When the difference between two results is larger than the estimates error, the result is</span>

3 0

2 years ago

Which of the following is NOT a geological event caused by the movement of tectonic plates?

photoshop1234 [79]

The answer is A. Mountains form because tectonic plates overlap. Earthquakes form because of the moving of tectonic plates. The moving of tectonic plates causes holes in the crust so magma from the mantle escapes and erupts from volcanoes. I hope I helped!

6 0

3 years ago

A block weighs 15 n and is suspended from a spring that is attached to the ceiling. the spring stretches by 0.075 m from its uns

Illusion [34]

We can salve the problem by using the formula:

$F=kx$

where F is the force applied, k is the spring constant and x is the stretching of the spring.

From the first situation we can calculate the spring constant, which is given by the ratio between the force applied and the stretching of the spring:

$k=\frac{F}{x}=\frac{15 N}{0.075 m}=200 N/m$

By using the value of the spring constant we calculated in the first step, we can calculate the new stretching of the spring when a force of 33 N is applied:

$x=\frac{F}{k}=\frac{33 N}{200 N/m}=0.165 m$

4 0

3 years ago