Is potential energy that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system
Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
The answer of this question is called uplift i.e the rising of rock layers in geology is called uplift.
Uplift is the process in which there will be vertical elevation of earth surface due to various natural processes occurring inside the surface of earth like earth quakes. Sometimes uplift is also caused by the mountain building which hampers the balance of a particular region.
In the process of uplift,the rocks normally metamorphic rocks present underground will be brought up to the earth surface.The enhanced elevation will cause erosion of lot of materials on the surface of earth.
Explanation:
Missing Details. Most models can't incorporate all the details of complex natural phenomena.
Most Are Approximations. Most models include some approximations as a convenient way to describe something
