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Vesna [10]
3 years ago
12

Which are charecteristics of eukaryotic organisms?

Engineering
2 answers:
miskamm [114]3 years ago
3 0
Eukaryotic cells are larger than prokaryotic cells and have a “true” nucleus, membrane-bound organelles, and rod-shaped chromosomes. The nucleus houses the cell's DNA and directs the synthesis of proteins and ribosomes.
Tasya [4]3 years ago
3 0
I don’t really understand this but I have a question that I don’t understand so sorry
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If anyone knows manufacturing plz help
sveta [45]

Answer:

I don't know ask my dad he would

Explanation:

but I can't ask him because he went to get milk and forgot to come back

8 0
3 years ago
Which of the following is not necessary a reason to machine a brake drum?
slamgirl [31]
Minor scoring should be your answer
6 0
3 years ago
A rigid tank holds 22 kg of 127 °C water. If 9 kg of that is liquid water what is the pressure in the tank and volume of the tan
ipn [44]

Answer:

The pressure and volume of the tank are 246.878 Kpa and 9.449 m³ respectively.

Explanation:

Volume is constant as the tank is rigid. Take the saturation condition of water from the steam table for pressure at 127°C.  

Given:  

Total mass of water is 22 kg.  

Mass of liquid water is 9 kg.  

Temperature of water is 127°C.  

From steam table at 127°C:  

The pressure in the tank is 246.878 Kpa.  

Specific volume of saturated water is 0.00106683 m³/kg.  

Specific volume of saturated steam is 0.72721 m³/kg.  

Calculation:  

Step1  

From steam table at 127°C:  

The pressure in the tank is 246.878 Kpa.  

Step2  

Dryness fraction is calculated as follows:  

x=\frac{m_{v}}{m_{t}}

Here, dyness fraction is x, mass of vapor is m_{v}and total mass is m_{t}.  

Substitute the values in the above equation as follows:  

x=\frac{m_{v}}{m_{t}}

x=\frac{22-9}{22}

x = 0.59  

Step3  

Specific volume of tank is calculated as follows:  

v=v_{f}+x(v_{g}-v_{f})

v=0.00106683+0.59(0.72721-0.00106683)

v=0.00106683+0.42842447

v=0.4295 m³/kg.  

Step4  

Volume is calculated as follows:  

V=v\times m_{t}

V=0.4295 \times22

V=9.449 m³.  

Thus, the pressure and volume of the tank are 246.878 Kpa and 9.449 m³ respectively.

8 0
4 years ago
The aluminum rod AB (G 5 27 GPa) is bonded to the brass rod BD (G 5 39 GPa). Knowing that portion CD of the brass rod is hollow
Temka [501]

Answer:

Qcd=0.01507rad

QT= 0.10509rad

Explanation:

The full details of the procedure and answer is attached.

7 0
4 years ago
If dhsjbejsjwnsjsjjfndjwks
Sholpan [36]

Answer:

dhsjbejsjwnsjsjjfndjwks

Thanks for the freeeeee pointssssss!

Explanation:

;p

5 0
3 years ago
Read 2 more answers
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