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lana [24]
3 years ago
12

GIVING BRAINLIEST TO THE RIGHT ANSWER examine the information for the two samples described in the chart. How are zinc and sodiu

m alike?
A. They have the same hardness at room temperature.

B. They are both dolids at room temperature.

C. They have the same color.

D. They have the same boiling point.
​

Physics
2 answers:
olasank [31]3 years ago
6 0
They’re both solids at room temperature; everything else was different for every other answers, but in each box it says “Stare at room temperature: solid” so, they’re both solids at room temperature
Liono4ka [1.6K]3 years ago
6 0
Well they both have the same mass of 9g. And they are both solids at room temp. So probably B
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A 2.50 gram rectangular object has measurements of 22.0 mm, 13.5 mm, and 12.5 mm. what is the object's density in units of g/ml?
Zinaida [17]
G/mL is equivalent to g/cm^3, so we first convert the dimensions into cm:
2.20 cm, 1.35 cm, and 1.25 cm
Then the total volume is: V = lwh = 3.7125 cm^3
To get the density, we divide mass by volume: 2.50 g / 3.7125 cm^3 = 0.6734 g/cm^3 = 0.6734 g/mL
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3 years ago
How do gases respond to changes in pressure and temperature?
kakasveta [241]
They compress or expand depending on amount of pressure or depending on the temperature
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3 years ago
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A voltage amplifier with an input resistance of 40k ohms, an output resistance of 100 ohms, and a gain of 300 V/V is connected b
AfilCa [17]

Answer:

89.45 v/v

Explanation:

Let's take the data:

First draw the amplifier circuit.

After the circuit, the voltage division rule can be used to compute the parameters:

The input section is computed like this: \frac{R_{in} }{(R_{sig}  + R_{in} }  (v_{sig})

The output section is computed like this R_{L}/ (R_out}  + R_{in} )

The product AV_{in} V_{out} gives

AV_{in} V_{out}  = A×\frac{R_{in} }{(R_{sig}  + R_{in} }  (v_{sig})×R_{L}/ (R_out}  + R_{in} )

Computing gives output voltage = 89.45 v/v

5 0
3 years ago
PLEWSE SOMEONE HELP ILL MARK BRAINLIST
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Answer:

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Explanation:

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3 0
3 years ago
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A 2kg block has 70J of KE. It then travels 1.5 meters up a hill. As it travels up the hill friction does -12J of work on the blo
Dima020 [189]

Answer:

v = 5.34[m/s]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the sum of the mechanical energy in the initial state plus the work on or performed by a body must be equal to the mechanical energy in the final state.

Mechanical energy is defined as the sum of energies, kinetic, potential, and elastic.

E₁ = mechanical energy at initial state [J]

E_{1}=E_{pot}+E_{kin}+E_{elas}\\

In the initial state, we only have kinetic energy, potential energy is not had since the reference point is taken below 1.5[m], and the reference point is taken as potential energy equal to zero.

In the final state, you have kinetic energy and potential since the car has climbed 1.5[m] of the hill. Elastic energy is not available since there are no springs.

E₂ = mechanical energy at final state [J]

E_{2}=E_{kin}+E_{pot}

Now we can use the first statement to get the first equation:

E_{1}+W_{1-2}=E_{2}

where:

W₁₋₂ = work from the state 1 to 2.

E_{k}=\frac{1}{2} *m*v^{2} \\

E_{pot}=m*g*h

where:

h = elevation = 1.5 [m]

g = gravity acceleration = 9.81 [m/s²]

70 - 12 = \frac{1}{2}*2*v^{2}+2*9.81*1.5

58 = v^{2} +29.43\\v^{2} =28.57\\v=\sqrt{28.57}\\v=5.34[m/s]

4 0
3 years ago
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