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jeka57 [31]
3 years ago
10

1.00 mL of a 3.05 × 10–4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether,

Chemistry
1 answer:
olchik [2.2K]3 years ago
4 0

Explanation:

plz mark as brainlist////

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What’s that’s balanced out
stiks02 [169]
Blank 1: nothing (to keep 2 total nitrogen)
blank 2: 3 (to make 6 total hydrogen)
blank 3: 2 (to make 2 total nitrogen and 6 total hydrogen)

hope this helps!! :)
7 0
3 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446
notsponge [240]

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
4 years ago
Read 2 more answers
When one form of energy is converted to another form in any physical or chemical change, energy input alwasy equals energy outpu
aliya0001 [1]
In the context of chemistry, yes. Energy input is always equal to the energy output.
5 0
3 years ago
What is the mass of sodium (Na) in 50 grams of table salt (NaCl)? Show your work.
Margaret [11]

Answer:

19 g

Explanation:

Data Given:

Sodium Chloride (table salt) = 50 g

Amount of sodium (Na) = ?

Solution:

Molecular weight calculation:

NaCl = 23 + 35.5

NaCl = 58.5 g/mol

Mass contributed by Sodium = 23 g

calculate the mole percent composition of sodium (Na) in sodium Chloride.

Since the percentage of compound is 100

So,

Percent of sodium (Na) = 23 / 58.5 x 100

Percent of sodium (Na) = 39.3 %

It means that for ever gram of sodium chloride there is 0.393 g of Na is present.

So,

for the 50 grams of table salt (NaCl) the mass of Na will be

mass of sodium (Na) = 0.393 x 50 g

mass of sodium (Na) = 19 g

8 0
4 years ago
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How do substances and mixtures diifer
vlabodo [156]

Answer:

hello hope this helps :)

a pure substance consists only of one element or one compound. a mixture consists of two or more different substances, not chemically joined together.

Explanation:

5 0
3 years ago
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