What is the pressure inside a container of 3 moles of gas with a volume of 60 Liters at a temperature of 400 K?

1 answer:

4 0

1.64 atm

PV = nRT —> P = nRT / V

n = 3 moles
R = 0.08206 L atm / mol K
T = 400 K
V = 60 L

P = (3)(0.08206)(400) / 60 = 1.64 atm

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