What is the pressure inside a container of 3 moles of gas with a volume of 60 Liters at a temperature of 400 K?
1 answer:
1.64 atm
PV = nRT —> P = nRT / V
n = 3 moles
R = 0.08206 L atm / mol K
T = 400 K
V = 60 L
P = (3)(0.08206)(400) / 60 = 1.64 atm
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