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Ulleksa [173]
3 years ago
10

Carbon dioxide can change directly from the solid phase to the gaseous phase. true or false

Chemistry
1 answer:
uysha [10]3 years ago
3 0
True, its called sublimation. (vice versa as well)
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How do you identify an element?
Reptile [31]

Answer:

element is the smallest particles which cannot be broken down.

5 0
3 years ago
Describe the relationship between Avogadro's number and one mole of any substance.
viktelen [127]
They are the same thing!
5 0
3 years ago
Read 2 more answers
Radiometric dating is the workhorse of absolute dating. If you had a sample with a radioactive component with a half-life of 500
PSYCHO15rus [73]
The amount left over after T years where P is initial amount is P( \frac{1}{2})^{ \frac{t}{5000} }
it halves each time so after t times of the 5000 years have elapsed, the amount is now (1/2)^t of the original amount

find how many half lives

10000/5000=2
(1/2)^2=1/4
1/4 of original amount after 10000 years

after 50000 years
50000/5000=10
(1/2)^10=1/1024
1/1024 of original amount after 50000 years


it dissapears when it attains an amount you deem is nigligible, so if you had 1 mol of subsutance, you might say it dissapears when it gets to 10^-23 or about 6.02 molecules



5 0
4 years ago
What is the boiling point of a solution made by mixing 75.0g ZnCl2 with 375.0 grams of water? (Kb for water is 0.512 C/m)
monitta
The problem can be solved using the following formula:

ΔTb = i Kb <em>m</em>

i = moles particles/moles solute
Kb = 0.512 °C/m
m = molality =  moles solute/kg solvent

First we can solve for the molality of the solution:

75.0 g ZnCl₂ / 136.286 g/mol = 0.550 mol ZnCl₂

m = 0.550 mol/0.375 kg
m = 1.468 mol/kg

We can now solve for the change in temperature of the boiling point:

ΔTb = i Kb m
ΔTb = (3 mol particles/1 mol ZnCl₂) (0.512 °C/m) (1.468 m)
ΔTb = 2.25 °C

The boiling point of a solution is the initial boiling point plus the change in boiling point:

BP = 100 °C + 2.25 °C
BP = 102.25 °C

The solution will have a boiling point of 102.25 °C.
5 0
3 years ago
The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?
juin [17]

The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

Density = \frac{mass}{volume}

Mass = 1.0 g/ml\times 1000 mL = 1000 g

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = \frac{1000 g}{18 g/mol} = 55.55 mol

Substituting the values in formula (1):

mole fraction = \frac{0.001}{55.55+0.001}

mole fraction = 1.8\times 10^{-5}

Hence, the mole fraction is 1.8\times 10^{-5}.

7 0
3 years ago
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