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Over [174]
4 years ago
13

Написать сочинение на тему маленький человечек​

Physics
1 answer:
slega [8]4 years ago
5 0
ꫝꪮꪀᧁ ꪮꪑᧁ ꪗρꫀ ꫝꪗ ᧁꪮᧁ ꪀ ꪀ ꫝ ꪊᠻᠻ ᦔ ᭙ꫝꪖ ꪗꪮꪊ ꪖꪀᧁ
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HELLLLPPPPPPPPPPPPPPPPPPPPPP PLZZZZ AND THANK YOU
makvit [3.9K]

Answer:

The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.

Explanation:

If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.

7 0
3 years ago
What is the slope of (0,0)(4,200)
Kruka [31]

Answer:

.02

Explanation:

X-x/ Y-y= 4-0/200-0 =.02

5 0
3 years ago
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What are lowland areas on the moon
PolarNik [594]
Craters flat land or rock
3 0
3 years ago
A loop of wire is placed in a uniform magnetic field. (a) For what orientation of the loop is the magnetic flux a maximum? The p
ra1l [238]

Answer:

1) The plane of the loop is perpendicular to the magnetic field.

2) The magnetic flux is independent of the orientation of the loop.p

Explanation:

The flux is calculated as φ=BAcosθ. The flux is therefore the highest when the magnetic field vector is perpendicular to the plane of the loop We can also deduce that the flux is zero when there is no magnetic field part perpendicular to the loop When the angle reaches zero, the flux is in the limit because when the angle becomes zero, the cos is the maximum.

5 0
3 years ago
The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime
nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

x=10\ sin2t+15\ cos2t+100

At t = 1 s

x=10\ sin2+15\ cos2+100

x = 115.33 mm

(a) We know that,

Velocity, v=\dfrac{dx}{dt}

v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}

v=20\ cos2t-30\ sin2t

At t = 1 s

v=20\ cos2-30\ sin2

v = 18.94 mm/s

We know that,

Acceleration, a=\dfrac{dv}{dt}

a=\dfrac{d(20\ cos2-30\ sin2)}{dt}

a=-40\ cos2t-60\ cos2t

At t = 1 s

v=-40\ cos2-60\ cos2

a=-99.93\ mm/s^2

(b) For maximum velocity, \dfrac{dv}{dt}=a=0

-40\ cos2t-60\ cos2t=0

t = 45 seconds

For maximum acceleration, \dfrac{da}{dt}=0

80\ sin2t+120\ cos2t=0

t = 61.8 seconds

Hence, this is the required solution.

5 0
4 years ago
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