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finlep [7]
2 years ago
15

In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15

m/s. The Astronaut’s mass is 70kg. What is his Velocity?
Physics
1 answer:
Cloud [144]2 years ago
8 0

Answer: -8.5 × 10^-4 m/s

Explanation:

The following can be deduced from the question:

m₁ = Mass of a wrench = 4 g = 0.004 kg

v₁ =Speed of wrench = -15 m/s

m₂ = Mass of the Astronaut = 70 kg

The velocity will be calculated as:

m₁v₁ = m₂v₂

v₂ = [0.004 × (-15)] / 70

= -8.5 × 10^-4 m/s

Therefore, the velocity is -8.5 × 10^-4 m/s

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A bungee cord is 30m long and when stretched a distance x itexerts a restoring force of magnitude kx. Your father-in-law (mass95
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Answer:

The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.

Explanation:

As from the given data

the length of the rope is given as l=30 m

the stretched length is given as l'=41m

the stretched length required is give as  y=l'-l=41-30=11m

the mass is m=95 kg

the  force is  F=380 N

the gravitational acceleration is g=9.8 m/s2

The equation of  k is given by equating the energy at the equilibrium point which is given as

U_{potential}=U_{elastic}\\mgh=\dfrac{1}{2} k y^2\\k=\dfrac{2mgh}{y^2}

Here

m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so

k=\dfrac{2mgh}{y^2}\\k=\dfrac{2\times 95\times 9.8\times 41}{11^2}\\k=630.92 N/m

Now the force is

F=kx\\ or

x=\dfrac{F}{k}\\

So here F=380 N, k=630.92 N/m

x=\dfrac{F}{k}\\x=\dfrac{380}{630.92}\\x=0.602 m

So the distance is 0.602 m

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