Answer:
sorry your test account help us to do with your own
Answer:
the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.
Explanation:
Given:
f₁ = frequency = 266 Hz
f₂ = 400 Hz
Question: How do the wavelength of each of these sound waves compare, λ₁ = ?, λ₂ = ?
The equation to solve this question is
Here
λ = wavelength of the sound
v = speed of sound = 340 m/s
f = frequency of each instrument
You need to calculate both wavelengths
According to the results, the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.
Technically, carrying her team-mate horizontally
along a level surface (D) doesn't require any 'work'.
Before you begin, you need to first figure out what your problem gives you and what you need to look for.
Given:
vix=10m/s
dy= 20m
What you are looking for is horizontal distance or dx.
The formula for vertical distance is:
Where:
dx= horizontal distance
vix= initial horizontal velocity
t=time
But when you look at your problem, you do not have time. Now for time, you need to use the formula:
g in this equation is a constant. It is the acceleration due to gravity which has the value of 9.8m/s^2.
Now we first need to get time:
Now that you have time, all you need to do is insert that into our equation for horizontal distance.
The horizontal distance of the rock will be
20.20m.