Answer:
- 0.07 °C
Explanation:
At constant pressure and number of moles, Using Charle's law
Given ,
V₁ = 439 mL = 0.439 L ( 1 L = 0.001 mL )
V₂ = 0.378 L
T₁ = 317.15 K
T₂ = ?
Using above equation as:
The conversion of T(K) to T( °C) is shown below:
T( °C) = T(K) - 273.15
So, <u>T = 273.08 - 273.15 °C = - 0.07 °C</u>
The answer that would best complete the given statement above would be the term PHASE. Here is the complete statement. <span>A homogeneous portion of a mixture that is characterized by uniform properties and capable of being separated by mechanical means is called a PHASE. Hope this helps.</span>
Answer:
1023.75mmHg
Explanation:
V1 = 3.5L
P1 = 585mmHg
V2 = 2.0L
P2 = ?
To solve this question, we'll require the use of Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature is kept constant.
Mathematically,
V = kP, k = PV
P1 × V1 = P2 × V2 = P3 × V3 = .......= Pn × Vn
P1 × V1 = P2 × V2
Solve for P2,
P2 = (P1 × V1) / V2
P2 = (585 × 3.5) / 2.0
P2 = 2047.5 / 2.0
P2 = 1023.75mmHg
The final pressure of the gas is 1023.75mmHg
