Answer:
C. 1/4
Explanation:
Let's assume that the allele for the spotted coat is "S" and the one for the even coat is "s". The allele "L" gives short horns while the recessive allele "l" imparts long horns. The genotype of the cattle heterozygous for both traits would be SsLl. A cross between two heterozygous cattle would produce progeny in following phenotype ratio=
9 spotted coat and short horns: 3 even coat and short horns: 3 spotted coat and long horns: 1 even coat and long horns.
Therefore, the proportion of the progeny with long horns = 4/16= 1/4
The truth about blood buffering is that 1). mantains the ph of blood near to 7.4. 2) utilizes the H2CO3/HCO3– conjugate acid/base pair and 3) is facilitated by the enzyme carbonic anhydrase, which interconverts carbon dioxide and water to carbonic acid. Have in mind that the buffer is written as the following: <span>CO2(aq) + H2O(l) <==> H+(aq) + HCO3^-(aq) </span>
It's called telophase in mitosis
Answer:
Stomata
Explanation:
Photosynthesis is a unique phenomenon which occurs in the Chloroplast of plant cells. It is the way they synthesize their food in form of glucose. However, like every metabolic reaction, photosynthesis requires certain reactants and products.
Photosynthesis combines carbondioxide (CO2) gas and water (H2O) in the presence of sunlight to produce Glucose (C6H12O6) and oxygen gas (O2). The gaseous components of this metabolic activity enters (C02) and leaves (O2) the plant via a structure in the leaves called STOMATA.
STOMATA is a pore found in the epidermis layer of plant leaves that aids in the exchange of gases i.e. carbondioxide in, oxygen out during Photosynthesis.
5 chromosomes. Meiosis results in 4 haploid cells, meaning they have "n" pairs of chromosomes. The diploid cell that the 10 chromosomes originated in has "2n" pairs. This leaves us with a simple equation to solve the problem, 2n=10, so n must equal 5 chromosomes.
