Question

How many grams are in 0.75 moles of SO2

Answer 1

Answer:

48 g SO₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

0.75 mol SO₂

Step 2: Identify Conversions

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of SO₂ - 32.07 + 2(16.00) = 64.07 g/mol

Step 3: Convert

1. Set up:                              $\displaystyle 0.75 \ mol \ SO_2(\frac{64.07 \ g \ SO_2}{1 \ mol \ SO_2})$
2. Multiply/Divide:                $\displaystyle 48.0525 \ g \ SO_2$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

48.0525 g SO₂ ≈ 48 g SO₂