Answer:
- Elimination
- Elimination
- Zaitsev
- Zaitsev
- Carbocation
Explanation:
- The mechanism is generally accepted to always operate via an ELIMINATION step-wise process.
- The ELIMINATION mechanism process will always produce (after dehydration) a ZAITSEV style alkene as major product
- The driving force for the production of this ZAITSEV style alkene product is generally going to be determined by stability of the CARBOCATION
Elimination mechanism is the removal of two substituents from a molecule in either a one- or two-step mechanism
Carbocation is a molecule containing a positive charged carbon atom and three bonds
Answer:
5.3 × 10^-4 m or 0.0000053m
Explanation:
Wavelength is given by 2L/m
Where m is the waves bewtween the cavity mirrors which is 100000
L is the cavity length which is 53.00 cm
53/100 (convert to meter) =0.53m
Therefore the wavelength is (2 × 0.53m)/100,000
=0.0000053
= 5.3 × 10^-6 m
The Question is incomplete here is the complete question " Suppose an iron atom in the oxidation state +3 formed a complex with three hydroxide anions and three water molecules. Write the chemical formula of this complex.
Answer:
{Fe(OH)3(H20)3}
Explanation:
Oxidation state is the electron gained or lost by and atom, So if iron is in +3 state in formula it must have lost three electron.
We know that OH posses the oxidation state of -1 and water have zero oxidation state. SO, Let's take iron equal to y and find its oxidation state in the formula
y + 3 ( - 1 ) + 3 ( 0 ) = 0
y - 3 + 0 = 0
y-3=0
y= + 3
Hence it's proved that iron has +3 oxygen state.
Answer:
621.2090000000001 grams
Explanation:
1 moles Calcium to grams = 40.078 grams
15.5*40.078 = 621.2090000000001 g
Answer:
pH=4.63
Explanation:
The firt step is identify the <u>Acid</u> and the <u>conjugated base</u>:
HA <=> +
So, for this case we will have:
<=> +
Then:
HA =
=
With this in mind we can use the <u>henderson-hasselbach equation</u>:
pH = pKa + Log
We can calculate the <u><em>pKa</em></u> first
Then we can put the values in the equation:
pH = 4.2 + Log()
pH= 4.63