Answer:
C₁₂H₂₂O₁₁ (C₁₂H₂₂O₁₁ ).
Explanation:
The empirical formula is obtained when we divide the molecular formula with a whole number giving the simplest ratio of all the elements (in whole number).
a) C₁₂H₂₂O₁₁ :
There is no number with which we can divide the ratio further to get a simpler formula hence the molecular formula of the given compound is the empirical formula of the compound. Hence it is correct.
(C₁₂H₂₂O₁₁),
(b) C₈H₁₂O₄
The empirical formula can be obtained by dividing the formula with "4"
The empirical formula would be
(C₂H₃O)
(c) H₂O₂
The empirical formula would be (H₁O₁)
2.7 L in cm³ :
2.7 * 1000 = 2700 cm³
Weight = Volume * Density
2700 * 0.79 = 2133 g
1 Ibs = <span>453.59 g
2133 / 453.59 = 4.70 Ibs
hope this helps!</span>
Answer:
— Washing with soap and water is an effective way to destroy and dislodge many microbes
Explanation:
- Soap actually kill germs on our hands, it breaks them up and removes them
- .But soap molecules have two different ends to them.
- One end is attracted to water molecules – this is called hydrophilic
- – and the other end loves oil and fat molecules – this is called hydrophobic.
- Soap is able to bind to the oils on our hands, and then mix with the water to wash all the germs away.
This is an oxidation reaction. The balanced equation is as follows:
6H₂O + N₂ → 2NO₃⁻+ 12H⁺ + 6e⁻
Rules to balance redox reaction in acidic medium
- Write the given equation in ionic form
- Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
- Break the equation into two halfs
- Balance the half equations
A. Balance all other atoms except Oxygen and hydrogen
B. Balance oxygen by adding H2O to the side deficient in oxygen
C. Balance hydrogen by adding H+ ions
D. Balance charge by adding electrons
5. Add the two half such that electrons gets cancelled
Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.
N₂(g) → NO₃⁻(aq)
N₂ → 2NO₃⁻
6H₂O + N₂ → 2NO₃⁻
6H₂O + N₂ → 2NO₃⁻+ 12H⁺
- balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.
6H₂O + N₂ → 2NO₃⁻+ 12H⁺ + 6e⁻
Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.
learn more about balancing redox reactions at brainly.com/question/10203480
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