Answer:
Explanation:
It is possible to answer this question knowing Hess's law that says you can sum half-reactions enthalpy cahnge to obtain enthalpy change of the total reaction. Using the reactions:
<em>(1) </em>2NO(g) → N₂(g)+O₂(g) ΔH = -180,6 kJ
<em>(2) </em>N₂(g) + O₂(g) + Cl₂(g) → 2NOCl(g) ΔH = +103,4 kJ
The reverse reactions of (1) and (2) are:
<u>N₂(g)+O₂(g)</u> → 2NO(g) ΔH = +180,6 kJ
2NOCl(g) → <u>N₂(g) + O₂(g)</u> + Cl₂(g) ΔH = -103,4 kJ
The sum of these reactions is:
2NOCl(g) → 2NO(g) + Cl₂(g) ΔH = +180,6 kJ -103,4 kJ = <em>77,2 kJ</em>
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I hope it helps!
Answer:
A compressed gas cylinder is filled with 5270 g of argon gas.
The pressure inside the cylinder is 2050 psi at a temperature of 18C.
The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.
How many grams of argon remains in the cylinder?
Explanation:
First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:
Mass of Ar gas is --- 5270g.
The number of moles of Ar gas:
Temperature T=(18+273)K=291K
Pressure P=2050psi
Volume V=?
Using this volume V=22.6L
Pressure=650psi=44.2atm
Temperature T= (26+273)K=299K
calculate number of moles "n" value:
Mass of 40.7mol of Ar gas:
Answer:
The mass of Ar gas becomes 1625.8g.
Answer: 25.5°C
Explanation: take the average of the reading i.e (25 + 26)/2= 25.5
Answer: 0.4533mol/L
Explanation:
Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol
68g of CaCO3 dissolves in 1.5L of solution.
Xg of CaCO3 will dissolve in 1L i.e
Xg of CaCO3 = 68/1.5 = 45.33g/L
Molarity = Mass conc.(g/L) / molar Mass
Molarity = 45.33/100 = 0.4533mol/L
